Quote:
Originally Posted by ONeil
This is what I said

No, it is not. It is what you meant by it, but not what you actually said. But I understand now.
But there's a little sense in saying that. If the Mersenne number (2
^{p}1) is prime, there is no discussion about factors. If it's not a prime, well, the only other option is that it is composite, which means it does have prime factors, but if it has strictly more than 2 of them (all the time, except for a very small part of those numbers), then the product of any two prime factors is also a factor, but a composite one.