You can calculate what 1 Ghz-day is defined as in terms of FLOP (Floating Point operations):

https://www.mersenne.org/primenet/
Right now in the "Aggregate Computing Power" last 24 hours:

498.551 TFLOP/sec = 498,551 GFLOP/sec but it is also equal to: 249275 GHz-days.

So 1 Ghzdays is defined as 498551/249275 =

**2 GFLOP/sec for 24 hours** which is:

2 GFLOP/s * 86400 sec = 172,800 GFLOP = 172.8 TFLOP

So

**1 Ghz-days is 172.8*10**^{12} Floating Point operations.

But all the Ghz-days calculations are approximate, I think it is hard to determine the exact number of FLOP that LL, PRP, P-1, TF and ECM tests requires.