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Old 2020-08-16, 11:02   #14
JeppeSN
 
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"Jeppe"
Jan 2016
Denmark

2·83 Posts
Angry

I thought the problem would go away if you shifted away from zero (where the floating point number representation can shift almost arbitrarily), but it still cannot do any of:
Code:
solve(x=-1, 2, x^3)
solve(x=-1+0.1, 2+0.1, (x-0.1)^3) - 0.1
solve(x=-1+0.1, 2+0.1, print(x);(x-0.1)^3) - 0.1
with usual realprecision default. /JeppeSN
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