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 2020-04-13, 16:59 #7 Nick     Dec 2012 The Netherlands 11×151 Posts On your 1st sheet, you have $F(\zeta)=\sum_{r=1}^{q-1}A_r\zeta^r$ so there is no term with $$\zeta^0$$ (or $$\zeta^q$$ which is also 1). On your 2nd sheet, you apply the idea to a polynomial which does have a term with $$\zeta^0$$. Is the book you are using a well known one? If one of has it, perhaps we can help you pinpoint where the misunderstanding arises.