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 2020-04-13, 13:54 #4 Nick     Dec 2012 The Netherlands 31758 Posts Let's take your example of q=7. If $f_0\zeta^0+f_1\zeta^1+f_2\zeta^2+f_3\zeta^3+f_4\zeta^4+f_5\zeta^5= g_0\zeta^0+g_1\zeta^1+g_2\zeta^2+g_3\zeta^3+g_4\zeta^4+g_5\zeta^5$ where the $$f_i$$ and $$g_i$$ are polynomials with integer (or rational) coefficients then $$f_0=g_0$$, $$f_1=g_1$$,...,$$f_6=g_6$$. So it's not a problem if the polynomial F has a constant term. Replacing $$\zeta$$ with $$\zeta^m$$ permutes the coefficients of $$\zeta^1$$ up to $$\zeta^6$$ and leaves $$\zeta^0$$ unaltered. Last fiddled with by Nick on 2020-04-13 at 20:19 Reason: Corrected typo