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How to solve: k(b^m)-z=n*d. ?
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2018-03-09, 01:49
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science_man_88
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Jul 2009
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Quote:
Originally Posted by
JM Montolio A
Solve: 29(5^m)-11 = 13*D
Mod 5:
-1=3*D \\ D is 3 mod 5
Mod 13:
3(5^m)=-2 \\ m is congruent to 3 mod 12
Anyways.
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