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Old 2018-03-09, 01:04   #10
a1call
 
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"Rashid Naimi"
Oct 2015
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Quote:
Originally Posted by a1call View Post
How do you get
1+1*1+1*1*1+1*1*1*25+1*1*1*25*5+1*1*1*25*5*1

in
D = 1+1*1+1*1*1+1*1*1*25+1*1*1*25*5+1*1*1*25*5*1= 278.

Thanks in advance.
In particular the underlined 1

1+1*1+1*1*1+1*1*1*25+1*1*1*25*5+1*1*1*25*5*1

and why is there no +1*1*1*25*5*1*1
added to the end?

Is the added 1 and missing last addend a general rule or subject to variations?

Thank you for the reply.

Last fiddled with by a1call on 2018-03-09 at 01:04
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