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 2018-03-06, 18:35 #20 JM Montolio A   Feb 2018 1408 Posts I put some trace on the code. n 3 n 3 + e 1 = (2^g 2)(e' 1) n 3 M 2 Dbit 1 D 1 n 5 n 5 + e 1 = (2^g 1)(e' 3) n 5 + e 3 = (2^g 3)(e' 1) n 5 M 4 Dbit 2 D 3 n 7 n 7 + e 1 = (2^g 3)(e' 1) n 7 M 3 Dbit 1 D 1 n 9 n 9 + e 1 = (2^g 1)(e' 5) n 9 + e 5 = (2^g 1)(e' 7) n 9 + e 7 = (2^g 4)(e' 1) n 9 M 6 Dbit 3 D 7 n 11 n 11 + e 1 = (2^g 2)(e' 3) n 11 + e 3 = (2^g 1)(e' 7) n 11 + e 7 = (2^g 1)(e' 9) n 11 + e 9 = (2^g 2)(e' 5) n 11 + e 5 = (2^g 4)(e' 1) n 11 M 10 Dbit 5 D 93 n 13 n 13 + e 1 = (2^g 1)(e' 7) n 13 + e 7 = (2^g 2)(e' 5) n 13 + e 5 = (2^g 1)(e' 9) n 13 + e 9 = (2^g 1)(e' 11) n 13 + e 11 = (2^g 3)(e' 3) n 13 + e 3 = (2^g 4)(e' 1) n 13 M 12 Dbit 6 D 315 n 15 n 15 + e 1 = (2^g 4)(e' 1) n 15 M 4 Dbit 1 D 1 n 17 n 17 + e 1 = (2^g 1)(e' 9) n 17 + e 9 = (2^g 1)(e' 13) n 17 + e 13 = (2^g 1)(e' 15) n 17 + e 15 = (2^g 5)(e' 1) n 17 M 8 Dbit 4 D 15 n 19 n 19 + e 1 = (2^g 2)(e' 5) n 19 + e 5 = (2^g 3)(e' 3) n 19 + e 3 = (2^g 1)(e' 11) n 19 + e 11 = (2^g 1)(e' 15) n 19 + e 15 = (2^g 1)(e' 17) n 19 + e 17 = (2^g 2)(e' 9) n 19 + e 9 = (2^g 2)(e' 7) n 19 + e 7 = (2^g 1)(e' 13) n 19 + e 13 = (2^g 5)(e' 1) n 19 M 18 Dbit 9 D 13797 n 21 n 21 + e 1 = (2^g 1)(e' 11) n 21 + e 11 = (2^g 5)(e' 1) n 21 M 6 Dbit 2 D 3 n 23 n 23 + e 1 = (2^g 3)(e' 3) n 23 + e 3 = (2^g 1)(e' 13) n 23 + e 13 = (2^g 2)(e' 9) n 23 + e 9 = (2^g 5)(e' 1) n 23 M 11 Dbit 4 D 89 n 25 n 25 + e 1 = (2^g 1)(e' 13) n 25 + e 13 = (2^g 1)(e' 19) n 25 + e 19 = (2^g 2)(e' 11) n 25 + e 11 = (2^g 2)(e' 9) n 25 + e 9 = (2^g 1)(e' 17) n 25 + e 17 = (2^g 1)(e' 21) n 25 + e 21 = (2^g 1)(e' 23) n 25 + e 23 = (2^g 4)(e' 3) n 25 + e 3 = (2^g 2)(e' 7) n 25 + e 7 = (2^g 5)(e' 1) n 25 M 20 Dbit 10 D 41943 n 27 n 27 + e 1 = (2^g 2)(e' 7) n 27 + e 7 = (2^g 1)(e' 17) n 27 + e 17 = (2^g 2)(e' 11) n 27 + e 11 = (2^g 1)(e' 19) n 27 + e 19 = (2^g 1)(e' 23) n 27 + e 23 = (2^g 1)(e' 25) n 27 + e 25 = (2^g 2)(e' 13) n 27 + e 13 = (2^g 3)(e' 5) n 27 + e 5 = (2^g 5)(e' 1) n 27 M 18 Dbit 9 D 9709 n 29 n 29 + e 1 = (2^g 1)(e' 15) n 29 + e 15 = (2^g 2)(e' 11) n 29 + e 11 = (2^g 3)(e' 5) n 29 + e 5 = (2^g 1)(e' 17) n 29 + e 17 = (2^g 1)(e' 23) n 29 + e 23 = (2^g 2)(e' 13) n 29 + e 13 = (2^g 1)(e' 21) n 29 + e 21 = (2^g 1)(e' 25) n 29 + e 25 = (2^g 1)(e' 27) n 29 + e 27 = (2^g 3)(e' 7) n 29 + e 7 = (2^g 2)(e' 9) n 29 + e 9 = (2^g 1)(e' 19) n 29 + e 19 = (2^g 4)(e' 3) n 29 + e 3 = (2^g 5)(e' 1) n 29 M 28 Dbit 14 D 9256395 n 31 n 31 + e 1 = (2^g 5)(e' 1) n 31 M 5 Dbit 1 D 1