Calculating E based on B1
I have a quick question about a small part of the P1 algorithm. I accept that it is not efficient to store 3^{2EP}, but have a question about calculating the E. So, I will use a specific example in order to see if I fully grasp the concept. Let B1=10000, and ignore B2. The E is calculated based on (this is the question, please confirm) (9973 primorial)*(97 primorial)*(19 primorial)*(7 primorial)*(5 primorial)*(3^3*2^8). Is there any way to simplify this in layman's terms, or is this about as simplified as it gets?
Thanks for the help!
Johann
