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Old 2009-04-10, 01:20   #1
Batalov
 
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2

915810 Posts
Default Simple Diophantine equation

a^3 = b^5 + 100
Is there more than one solution?




________
P.S. Argh, I only started playing with modular restrictions, and you've already looked up to 10^35.
If so, then of course I am convinced, too. Sorry, then it was ...too simple.

Last fiddled with by Batalov on 2009-04-10 at 02:12
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