Thread: Combinatorics
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Old 2006-05-12, 19:25   #6
tom11784's Avatar
Aug 2003
Upstate NY, USA

32610 Posts

If you number the subsets by ranking from least to greatest for first term, then second term, then third term, then fourth
i.e. A1={1,2,3,4} A2={1,2,4,3} A3={1,3,2,4} A4={1,3,4,2} ...

and f({a,b,c,d})={a,b,c}

then B1={1,2,3} B2={1,2,4} B3={1,3,2} B4={1,3,4} ...

which I believe meets your requirements, but I may be reading something incorrectly
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