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Old 2008-04-27, 19:53   #10
frmky
 
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Jul 2003
So Cal

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Quote:
Originally Posted by davieddy View Post
I assume that an indefiniite integral was impossible (or at least difficult).
I think so. I suspect the square roots were there to ensure it since, interestingly, the answer does not depend on the power of the logs.

Greg
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