Thread: Sequence
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Old 2020-03-21, 15:18   #4
Citrix
 
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Jun 2003

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For k=3

S(0)=0
S(1)=(1-0)/3=1/3
S(2)=(1-1/3)/3=2/9
S(3)=(1-2/9)/3=7/27
...

Hope this helps
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