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k*b^n+/-c where b is an integer greater than 2 and c is an integer from 1 to b-1
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2016-04-23, 11:15
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axn
Jun 2003
5,189 Posts
Are you saying that if one studies jjsieve source, one will find a new method to test numbers of the form k*b^n+/-c?
axn
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