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 2019-07-01, 20:00 #1 wildrabbitt   Jul 2014 3·149 Posts dividing an algebraic integer by another Hi, I've worked out that the algebraic integer $$6+23\sqrt{2}$$ is divisible by $$2+\sqrt{2}$$. I find finding these factors by looking at norms quite tiring. Is another way to work out $$\frac{6+23\sqrt{2}}{2+\sqrt{2}}$$ in it's simplest form? A division algorithm for example. Please show me how it goes. Last fiddled with by wildrabbitt on 2019-07-01 at 20:04