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Forum: Miscellaneous Math 2022-07-08, 18:16
Replies: 1
Views: 127
Posted By RomanM
On the mod(x^2,p)=mod(x^2,p^2)=mod(x^2,p^3) = and so on

at the sample, let p =101*109 and x = 583379708211
x^2 mod p ==x^2 mod p^2 ==x^2 mod p^3 == x^2 mod p^4 =3955

I guess, for any n, p, x in Z, there is x, x^2 mod p^(n-k) == B for k = 0,..,n-1;
Forum: Miscellaneous Math 2022-06-23, 12:20
Replies: 2
Views: 250
Posted By RomanM
some symmery ListPlot[mpoint[#, 4] & /@...

some symmery
ListPlot[mpoint[#, 4] & /@ ((Prime[#]/EulerPhi[#]) & /@ Range[15000]),
Axes -> True, AspectRatio -> Automatic]
on the graph is connection Euler Phi(n) and n-prime number, and it's...
Forum: Miscellaneous Math 2022-06-18, 19:57
Replies: 2
Views: 250
Posted By RomanM
Hello. ListPlot[mpoint[#, 4] & /@ ((Prime[2*#]...

Hello.
ListPlot[mpoint[#, 4] & /@ ((Prime[2*#] - 2*Prime[#]) & /@
Range[15000]), Axes -> True, AspectRatio -> Automatic]
what do you think, is it possible to have a prime related function...
Forum: Miscellaneous Math 2022-06-12, 16:27
Replies: 2
Views: 250
Posted By RomanM
Ulam spirale, envolved to

Hi.
Plot code was taken from here
https://community.wolfram.com/groups/-/m/t/1543056

mgonLayer[q_, m_] := Ceiling[1/2 (1 + Sqrt[-8 + m + 8 q]/Sqrt[m])] - 1

maround[q_, m_] := q - (1 + m/2...
Forum: Miscellaneous Math 2022-01-31, 20:05
Replies: 19
Views: 1,621
Posted By RomanM
it is common knowledge that \lim_{n \rightarrow...

it is common knowledge that \lim_{n \rightarrow \infty}\frac{sin(n+1)\phi}{sin(n\phi)}=e^{i\phi}

its joke, on 50/50 percent)
If every prime number can be associated with a "prime angle" i.e....
Forum: Miscellaneous Math 2022-01-24, 19:55
Replies: 17
Views: 1,802
Posted By RomanM
prime numbers boring. take a look into prime...

prime numbers boring. take a look into prime angles
Forum: Miscellaneous Math 2022-01-24, 10:47
Replies: 17
Views: 1,802
Posted By RomanM
997 shot of "vaccine "gives immortality

997 shot of "vaccine "gives immortality
Forum: Miscellaneous Math 2021-12-22, 14:11
Replies: 2
Views: 431
Posted By RomanM
Ok. Thank You. I won't even ask why

Ok. Thank You.
I won't even ask why
Forum: Miscellaneous Math 2021-12-22, 13:59
Replies: 2
Views: 431
Posted By RomanM
An extension of NFS

Hi.
Both QS and NFS stuck with famouse A^2==B^2 mod p.
If we look on the A^3==B^3 mod p that do the split also (30% vs 50% for quadratic)
and in general to A^n==B^n*m & B^m=y mod p?? (1)
as a...
Forum: Homework Help 2021-12-15, 18:47
Replies: 2
Views: 1,153
Posted By RomanM
Casus of x^3+1

Do You know that
(2*(x^2+1)^3-7))^2\equiv3^4\ mod\ x^3+1
for all x in Z, abs(x)>=5???
Forum: Miscellaneous Math 2021-12-01, 16:37
Replies: 1
Views: 414
Posted By RomanM
Approximation of r by m^(1/n)

r\pm\epsilon=\sqrt[n]{m}
where r - real root of polynomial P(r), order >=6, and m, n - integers, and P(r+/-eps)<1
P.S. I'm suspect that the simpler the question look like, the less likely it is to...
Forum: Miscellaneous Math 2021-11-18, 17:43
Replies: 7
Views: 733
Posted By RomanM
I'm slowly came to understand this! Thanks! ...

I'm slowly came to understand this! Thanks!
this originlal formula.
mod((a*m^3+1/2*a*C)^2,m^5+C*m^2-1/4*a^2*C^2-4/a^2*m)=A
a=2, C=1 and we have a silly me with super obvios (2m^3+1)^2=blah...
Forum: Miscellaneous Math 2021-11-18, 15:42
Replies: 7
Views: 733
Posted By RomanM
And what? nor m^5+1, m^2*(m^3+1)= m^5+m^2 I...

And what?
nor m^5+1, m^2*(m^3+1)= m^5+m^2 I make an error here
if we take some big m and compute mod((2*m^3+1)^2, m^5+m^2)=1, than compute
mod((2*m^3+1)^2, m^5+m^2+1)=A, A will be relative small...
Forum: Miscellaneous Math 2021-11-18, 11:11
Replies: 7
Views: 733
Posted By RomanM
(2x^{3}+y^{3})^{2}\equiv y^{6}\;...

(2x^{3}+y^{3})^{2}\equiv y^{6}\; mod\;x^{2}(x^{3}+y^{3}); \; y\neq0,\; x,y\in Z

i.e. A^2==B^2 mod p, p=x^2(x^3+y^3); May be this too obviosly and known??? Let y=1 and we can easy factor m^5+1 for...
Forum: Miscellaneous Math 2021-11-16, 17:18
Replies: 5
Views: 1,127
Posted By RomanM
https://www.alpertron.com.ar/ECM.HTM

https://www.alpertron.com.ar/ECM.HTM
Forum: Miscellaneous Math 2021-11-16, 15:05
Replies: 7
Views: 733
Posted By RomanM
Thank You for the answer! The above arose from...

Thank You for the answer! The above arose from this (2m^{3}\pm1)^{2}\equiv1\; mod\;m^{5}\pm m^{2}
but m^5+-m^2 is narrow number to match any chosen p. If m=x/y; all much more interesting; if we...
Forum: Miscellaneous Math 2021-11-16, 10:11
Replies: 584
Views: 77,888
Posted By RomanM
Here is her Temple. There are also Prophets and...

Here is her Temple. There are also Prophets and Archbishops, followers and sinners) Perhaps there is even a Pope?
Forum: Miscellaneous Math 2021-11-16, 08:49
Replies: 7
Views: 733
Posted By RomanM
A small question from the lost book

I'm found this in the old book, that imply a solution; there are missing pages

Let x^{2}(x^{3}+y^{3})=p+\epsilon \quad x,y,p,\epsilon \in\ Z

How to find the smallest value of epsilon for given...
Forum: Miscellaneous Math 2021-11-16, 08:23
Replies: 584
Views: 77,888
Posted By RomanM
She is The Goddess Who Must Not Be Named) On the...

She is The Goddess Who Must Not Be Named) On the Earth and Discworld (by Terry Pratchett), also known as (again see the First rule), as Mrs. L.
Forum: Miscellaneous Math 2021-11-11, 20:32
Replies: 584
Views: 77,888
Posted By RomanM
it's not meant to be, as say mrs. F!

it's not meant to be, as say mrs. F!
Forum: Miscellaneous Math 2021-10-13, 15:15
Replies: 52
Views: 4,887
Posted By RomanM
Indeed. His omniscience suggests that it is...

Indeed. His omniscience suggests that it is necessary to substantially limit both omnipotence and omniscience. and then holy Bible marasmus and mersenneforum are not far away

I asked my neighbor...
Forum: Miscellaneous Math 2021-10-12, 17:29
Replies: 52
Views: 4,887
Posted By RomanM
***

God is almighty. ok. Let God create a BIG Stone, that is too big to god can't lift by blessed god arms, ok Seems that God is not too Almighty??? No. it's obviously. He just do not do such things.
Forum: Miscellaneous Math 2021-08-26, 15:01
Replies: 0
Views: 485
Posted By RomanM
Inverse of FFT multiplication?

on the sample
101*109=11009 (1)
let x=10
x^4+x^3+9
at the same time
(x^2+1)*(x^2+9)=x^4+10*x^2+9
i.e.
x^4+x^3+9-(x^3-10*x^2)=x^4+10*x^2+9
Bold polinomial exist for any composite.
So if we...
Forum: Dobri 2021-08-26, 13:25
Replies: 53
Views: 7,518
Posted By RomanM
100+ years old talk to Doctor -friend of...

100+ years old talk to Doctor

-friend of mine tell me, that he can have sex in row at the one night, and I can not, Help me!
-Ok, its very easy to Help! You just can tell him that You can do the...
Forum: Miscellaneous Math 2021-08-20, 14:57
Replies: 45
Views: 6,027
Posted By RomanM
Much better this way, this series converges...

Much better this way, this series converges absolutely) sum = sum + (-1)^n/Mexponent[[n]]
Showing results 1 to 25 of 51

 
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