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Forum: Puzzles 2021-11-15, 15:12
Replies: 31
Views: 18,304
Posted By R. Gerbicz
Thanks for the idea, then I'll try the AMM first,...

Thanks for the idea, then I'll try the AMM first, need to write down the solution.
It is a somewhat recreational Maths problem, but worth a paper.
Forum: Puzzles 2021-11-02, 10:51
Replies: 31
Views: 18,304
Posted By R. Gerbicz
There was a request to explain this more, took me...

There was a request to explain this more, took me some time to understand some tricks.

First why parity is so important here. It is trivial: for each c=-24..24 we choose T(c,0) or T(c,1), exactly...
Forum: Puzzles 2018-03-17, 09:05
Replies: 31
Views: 18,304
Posted By R. Gerbicz
Thanks for your interest! I"ve constructed all...

Thanks for your interest!
I"ve constructed all basic sequences that holds this, and then by induction we still maintain this. Note that all integers in [1,24] is free, because T(c,0) and T(c,1)...
Forum: Puzzles 2018-01-23, 21:59
Replies: 31
Views: 18,304
Posted By R. Gerbicz
I've thought the same in the recent days, maybe...

I've thought the same in the recent days, maybe I'll come up with a paper.
Forum: Puzzles 2018-01-21, 17:09
Replies: 31
Views: 18,304
Posted By R. Gerbicz
There is a solution for every n>=25 ! Giving a...

There is a solution for every n>=25 !
Giving a Hamiltonian cycle for all n>=32, see my linked code:
https://drive.google.com/file/d/1XpYRdJR00CldIfssjDW1clkh-HdPA708/view
somewhat large file ( 5.7...
Forum: Puzzles 2018-01-17, 22:26
Replies: 31
Views: 18,304
Posted By R. Gerbicz
Correct, but the goal was to prove that n>=25 is...

Correct, but the goal was to prove that n>=25 is in the sequence. Since it wasn't reached I've posted the above weaker result.



Yes, you need odd square, otherwise c=k^2/2 gives the same...
Forum: Puzzles 2018-01-17, 21:15
Replies: 31
Views: 18,304
Posted By R. Gerbicz
Returning to the original square-sum problem, a...

Returning to the original square-sum problem,
a non trivial result: the sequence is infinite, for n=(71*25^k-1)/2 there is a solution for every k>=0 integer.

For given "a" sequence that is a...
Forum: Puzzles 2018-01-12, 23:58
Replies: 31
Views: 18,304
Posted By R. Gerbicz
Nice problem, easily outperformed that in one day...

Nice problem, easily outperformed that in one day of work.

There exists a solution for n=15,16,17,23 and for all 25<=n<=1048576. (the last checked is n=2^20).
To prove more we give a Hamiltonian...
Showing results 1 to 8 of 8

 
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