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Forum: PrimeNet 2021-01-27, 09:29
Replies: 2
Views: 343
Posted By gLauss
Ok, this was not obvious to me. I always assumed...

Ok, this was not obvious to me. I always assumed it would calculate 3^{\frac{2^n-1}{p}} \text{ mod } \frac{2^n-1}{p} instead (assuming p is one or more factor). Then the residues would be different.
Forum: PrimeNet 2021-01-27, 08:14
Replies: 2
Views: 343
Posted By gLauss
C-PRP residue identical with different factors

Hi, yesterday I did just for fun a P-1 test for the small, already factored number M3331331 (https://www.mersenne.org/report_exponent/?exp_lo=3331331&full=1). This number had one known factor and two...
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