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[QUOTE]Also, x^5-843714919 is the correct one.[/QUOTE]
Ah, good point, I was confusing sigma(x^18) and x^18-1 ... that would make the algebraic side around 10^44 for the quintic, so that's the way to go. Probably not worth restarting the job. |
Not quite sure what happened there, I think I must have edited apocalypse's post rather than replying to it.
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Hi!
Received following messages today: [CODE]FBsize 1149879+0 (deg 5), 1151366+0 (deg 1) total yield: 572566, q=43000019 (0.85104 sec/rel) 113431 Special q, 367095 reduction iterations reports: 316699993->3967808970->3499071217->617340989->189940885->79581099 Number of relations with k rational and l algebraic primes for (k,l)=: Total yield: 572566 milliseconds total: Sieve 294360313 Sched 0 medsched 21601276 TD 51687587 (Init 801049, MPQS 80555) Sieve-Change 85867914 TD side 0: init/small/medium/large/search: 823253 3152762 1637884 10636302 12641 999 sieve: init/small/medium/large/search: 3001799 39113818 2193568 95135990 2269319 8 TD side 1: init/small/medium/large/search: 774681 862414 1638581 10464387 820494 3 sieve: init/small/medium/large/search: 2204269 28042425 2253189 95940634 3781423 [/CODE] What happens, please advice |
This is the usual message when the sieiving finishes its requested job.
[strike](looks like you were sieiving for the c171 for aliq.4788?) (probably not)[/strike] Did you sieve in one single run -f 41000000 -c 2000000 (judging by the number of special q's)? Not that there's anything wrong with it, but it is more convenient to sieve in chunks; easier to parallelize etc (you will also get slightly more relations, because FB_lim will be rising together with the -c value and not be frozen at 41000000). Your yield is low (572566 from a 2M q-range?); parameters that you are using are a bit suspect, as some people may say. What is the number? |
Hi, tanx, number is C155
i running many jobs for each core at each PC. yes, the yield is low, but i searched for a good poly about a week and didnt find better. Poly is: [CODE]m: skew: 404308.59 # norm 1.71e+021 c5: 69977040 c4: -40919910306512 c3: -38951048564673876494 c2: 6659089867695790241111157 c1: 2469483236376026733832761212030 c0: -84022074362447707231091322472985569 # alpha -6.13 Y1: 1396353296355407797 Y0: -163635006307491521022993089052 type: gnfs rlim: 18000000 alim: 18000000 lpbr: 28 lpba: 28 mfbr: 52 mfba: 52 rlambda: 2.6 alambda: 2.6 [/CODE] average speed is 0.54 sec/rel at Clock 3.2 Ghz of Core2Quad. |
Collectet 23000 unique relations on 9-95M range.
No success, 'filtering wants more 1 000 000 relations...' any idea to improve yield ? maybe i have to chose different poly ? tanx |
Is it 23 million or 23 thousand?
If 23 million, then are they really unique (if they were unique, it should have converged)? What is the filtering output, in detail? [COLOR=green]P.S. If you think that your N is so secret, you should have obscured some digits in your polynomials.[/COLOR] [COLOR=green]Because your number is their common root, it is easily computed. It is [/COLOR][URL="http://factordb.com/search.php?id=16325400"][COLOR=green]http://factordb.com/search.php?id=[/COLOR][COLOR=green]16325400[/COLOR][/URL][COLOR=green] and it is a [I]C154[/I] (but it does have 512 bits).[/COLOR] |
[QUOTE=Batalov;208560]
[COLOR=green]P.S. If you think that your N is so secret, you should have obscured some digits in your polynomials.[/COLOR] [/QUOTE] [COLOR="Olive"]Shhhhh! -----BEGIN PGP MESSAGE----- Version: GnuPG v1.4.9 (MingW32) hQQOA0FupPU0EeiyEA/+OQXrC+qRZrzqEtN88S/eJYDB6ujx/38PYGW9DALP1xVK LUemjpC9aSslVFDzWwzag0NYLgSiZsPlbPDAhVBKTf0VhO+6+F1YnxvXtsLkp3aE sf0BMHogdpBF5z0Y1WzNlNCeya7DHPlM3muPe1xXPs63rq9prrkH8uKrALgJjUuK jnWlqkVboukg7ciuvEnXhal/D4PQypiziAr53kmjHQJeVDkSnwJgMhcSqHCvDdmA Klro4gtzDFc6ALy+Bfns2LBpBvcY7roiFjX7E18rHQZiONrXNbRl3TAP5oBf/3Nl vhjtwe/a6jW4p+9uRvmNOfpgJhjdweHVGBigKBXH =g/BY -----END PGP MESSAGE-----[/COLOR] |
[quote=Batalov;208560]
[COLOR=green]P.S. If you think that your N is so secret, you should have obscured some digits in your polynomials.[/COLOR] [COLOR=green]Because your number is their common root, it is easily computed. It is [/COLOR][URL="http://factordb.com/search.php?id=16325400"][COLOR=green]http://factordb.com/search.php?id=[/COLOR][COLOR=green]16325400[/COLOR][/URL][COLOR=green] and it is a [I]C154[/I] (but it does have 512 bits).[/COLOR][/quote] [code] Sun Jul 27 16:46:12 2008 Msieve v. 1.36 Sun Jul 27 16:46:12 2008 random seeds: 4f9eb0f9 c69b5c7a Sun Jul 27 16:46:12 2008 factoring 8209836131236623540106248032442393614982637631141339598467747244677911494877848116936777629774248859738700738214196985237506543807286694994580847683477459 (154 digits) Sun Jul 27 16:46:13 2008 searching for 15-digit factors Sun Jul 27 16:46:14 2008 commencing number field sieve (154-digit input) Sun Jul 27 16:46:14 2008 R0: -366501892512856641124573959989 Sun Jul 27 16:46:14 2008 R1: 153803794949520818707 Sun Jul 27 16:46:14 2008 A0: -609153808778499403500623798053669920 Sun Jul 27 16:46:14 2008 A1: 988756559882381766374145859260 Sun Jul 27 16:46:14 2008 A2: 6199402379998072308296273 Sun Jul 27 16:46:14 2008 A3: -3390691833060500638 Sun Jul 27 16:46:14 2008 A4: -9008320667086 Sun Jul 27 16:46:14 2008 A5: 1245300 Sun Jul 27 16:46:14 2008 size score = 7.632233e-16, Murphy alpha = -5.440536, combined = 4.680043e-15 Sun Jul 27 16:46:14 2008 Sun Jul 27 16:46:14 2008 commencing square root phase Sun Jul 27 16:46:14 2008 reading relations for dependency 1 Sun Jul 27 16:46:15 2008 read 2839528 cycles Sun Jul 27 16:46:30 2008 cycles contain 9501724 unique relations Sun Jul 27 16:48:43 2008 read 9501724 relations Sun Jul 27 16:50:12 2008 multiplying 14368592 relations Sun Jul 27 18:14:24 2008 multiply complete, coefficients have about 817.17 million bits Sun Jul 27 18:15:03 2008 initial square root is modulo 21440369 Sun Jul 27 20:34:15 2008 reading relations for dependency 2 Sun Jul 27 20:34:17 2008 read 2841381 cycles Sun Jul 27 20:34:28 2008 cycles contain 9504728 unique relations Sun Jul 27 20:36:30 2008 read 9504728 relations Sun Jul 27 20:37:59 2008 multiplying 14375930 relations Sun Jul 27 22:03:01 2008 multiply complete, coefficients have about 817.59 million bits Sun Jul 27 22:03:40 2008 initial square root is modulo 21628877 Mon Jul 28 00:25:30 2008 reading relations for dependency 3 Mon Jul 28 00:25:39 2008 read 2841027 cycles Mon Jul 28 00:25:50 2008 cycles contain 9501574 unique relations Mon Jul 28 00:28:08 2008 read 9501574 relations Mon Jul 28 00:29:36 2008 multiplying 14367656 relations Mon Jul 28 01:53:46 2008 multiply complete, coefficients have about 817.13 million bits Mon Jul 28 01:54:25 2008 initial square root is modulo 21422053 Mon Jul 28 04:13:39 2008 prp77 factor: 7525920029946**************************************************************** Mon Jul 28 04:13:39 2008 prp78 factor: 1090874750006***************************************************************** Mon Jul 28 04:13:39 2008 elapsed time 11:27:27 [/code] |
1 Attachment(s)
[quote=siew;208121]Hi, tanx, number is C155
i running many jobs for each core at each PC. yes, the yield is low, but i searched for a good poly about a week and didnt find better. [/quote] BEGIN POLY #skewness 450875.80 norm 2.35e+021 alpha -6.10 Murphy_E 2.61e-012 BEGIN POLY #skewness 458270.11 norm 3.92e+021 alpha -6.43 Murphy_E 2.54e-012 BEGIN POLY #skewness 508663.06 norm 4.05e+021 alpha -6.48 Murphy_E 2.58e-012 BEGIN POLY #skewness 508947.15 norm 5.71e+021 alpha -6.39 Murphy_E 2.57e-012 BEGIN POLY #skewness 522987.56 norm 8.65e+021 alpha -6.84 Murphy_E 2.57e-012 BEGIN POLY #skewness 557204.51 norm 2.17e+021 alpha -6.00 Murphy_E 2.67e-012 BEGIN POLY #skewness 594103.33 norm 4.21e+021 alpha -6.49 Murphy_E 2.55e-012 BEGIN POLY #skewness 594322.68 norm 7.63e+020 alpha -4.93 Murphy_E 2.54e-012 BEGIN POLY #skewness 605334.77 norm 2.04e+022 alpha -7.85 Murphy_E 2.55e-012 BEGIN POLY #skewness 690937.77 norm 7.44e+020 alpha -5.00 Murphy_E 2.52e-012 P.S The Post ( [url]http://mersenneforum.org/showpost.php?p=208573&postcount=405[/url] ) above, too for you. |
[QUOTE=siew;208121]
Poly is: [CODE] rlim: 18000000 alim: 18000000 lpbr: 28 lpba: 28 mfbr: 52 mfba: 52 [/CODE] You should play around with all six of these. Hint: larger. You will probably be able to pool your existing relations with any new ones you find, so don't throw out what you have so far. |
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