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k=11 tested to n=3.2M (started from n=3.0M).
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k=49 at n=2.55M
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Taking k=297 from n=1.1M
BTW, both k=219 and k=225 are now at n=1.2M |
I plan to test k=111 to 1.75M this fall. Thomas11 has agreed to take over testing of this k from 1.75M, and will be posting updates as he makes progress.
I expect to complete to 1.75M in November. -Curtis |
k=29 @ ~3.26M
k=253 @ 3M I plan to test both bases to 4M soon. |
Status report
k=25 tested till n=2.9M
k=43 tested till n=3.04M k=79 tested till n=2.27M k=101 tested till n=3.23M k=151 tested till n=3.04M |
k=127
[QUOTE=VBCurtis;234599]No progress on 127, 201, 245, 443. 127 should be complete to 4M and released in Jan. 269 should be complete to 2M and released in December.[/QUOTE]
[QUOTE=VBCurtis;251481]I have been testing a lot of RPS drive files, at the expense of my previous goals for 127 and 269. I plan to finish 263,245,281 to 1.4M this winter and release them. Anyone is welcome to reserve those any time starting at 1.4M.[/QUOTE] As a part of my next Williams Prime target of 127*128[SUP]n[/SUP]-1, I would like to reserve k=127 but only for mod(n;7)=0. Based on the above quotes and information on 15k.org I was wondering where to start: @ n=3.11M or higher (4M?) or perhaps k=127 is still reserved? |
Cruelty-
127 has gaps from 3700 to 3800 and 3870 to 3900 presently, otherwise is complete to 4M. I decided not to release it at 4M, but haven't done much work while sieving is active on this N-range. I don't mind you searching this k for your project, but I would appreciate it if you can build files for me to search with the tests you run removed. Is that possible? Rephrased, I'd like you to split the sieve into a file you run, and a file I run. Another comment to those quotes: I did release 263 and 281, but still have 245 reserved to 2M. |
VBCurtis - you've got a deal :smile:
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Taking k=23 from n=1.5M
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SlashDude released k=23, now taken by Peter.
AES released k=103, 141, 143, 167, and 199 all at n=1.1M I'm taking k=199. Please consider taking some of the remaining 4 as we would like to gradually push all k<300 towards n=1.3M or more. Thanks! |
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