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Imagine a precisely cut plank of wood "p" inches** long. The width and height do not matter but the shape is a perfect rectangular solid. Along the length, each inch is marked with a line.
If that board can not be cut into pieces along the inch markers ONLY such that you can rearrange them laterally (and without turning the pieces) into a rectangular shape that has different dimensions than the original board (breath!) then p is prime. ** inch is arbitrary of course. The turning limitation might not be necessary. I'd have to think about that some more. |
[QUOTE=ewmayer;99515]An integer p is prime iff no integer x in the range sqrt(p) <= x < p divides p.[/QUOTE]
An integer p is prime if and only if for all A,B, such that A^2 = B^2 mod p, then A=B mod p or A=-B mod p. |
[QUOTE=R.D. Silverman;99523]An integer p is prime if and only if for all A,B, such that A^2 = B^2 mod p,
then A=B mod p or A=-B mod p.[/QUOTE] Ah, but you had to explicitly reference the number 2 - that's a 10-yard penalty and loss of down for you, Bob. Oh wait, I just referenced 1 and 0 in my description of the penalty - that's [i]log(p)/log(sqrt(p))[/i] minutes in the penalty box for me... Aren't arbitrary puzzle rules great? |
[QUOTE=ewmayer;99526]Ah, but you had to explicitly reference the number 2 - that's a 10-yard penalty and loss of down for you, Bob. Oh wait, I just referenced 1 and 0 in my description of the penalty - that's [i]log(p)/log(sqrt(p))[/i] minutes in the penalty box for me...
Aren't arbitrary puzzle rules great?[/QUOTE] So change it to A*A and B*B. This isn't an issue of using the number 2, but rather one of notation. |
[QUOTE=R.D. Silverman;99530]So change it to A*A and B*B. This isn't an issue of using the number 2, but rather one of notation.[/QUOTE]I'm amazed that no-one has yet picked me up for using ln(e) in a polynomial to be evaluated at integer values of its variables. Had anyone done so I would have, of course, replaced them all with (x/x)
Paul |
[QUOTE=S485122;99478]Isn't insisting on the plural the same as saying "more than one" and thus an explicit reference to a specific integer ? Or would this be a to restrictive interpretation of the rules ?[/QUOTE]
Can the high command give a ruling on this? I can reword my answer to say "a person"<->"one". |
[QUOTE=xilman;99541]I'm amazed that no-one has yet picked me up for using ln(e) in a polynomial to be evaluated at integer values of its variables. Had anyone done so I would have, of course, replaced them all with (x/x)
Paul[/QUOTE] Paul, Using x/x would necessitate x\neq 0. |
Prime Number definitions:
1) A positive integer p is a prime or a prime number if it is a whole number larger than unity and its only positive divisors are the unit and itself. Every prime number has the property that if it divides a product then it must divide at least one of the factors [Euclid c.300 BC.] 2) A positive integer is prime if only *two* but only *two* distinct factors, are itself and unity Euclid books 7 and 8 regards a number as a line interval compounded of units and defines a prime as a number which can only be measured by the unit (not itself a number) It follows from both the above two definitions that unity is not a prime 3) A prime is an irreducible element of a unique factorization domain and is known as prime. These are for positive primes. To allow for negative primes we cannot define it without naming some numbers. Definition: the term can also be used in some other situations where division is meaningful. For instance in the context of all the integers an integer other than 0+-1 is a prime integer if its only integer divisions are +- 1 and +- n. Mally. |
[QUOTE=mfgoode;99600]Prime Number definitions:[/QUOTE]Mally,
I like to believe that all participants to the thread so far are well aware of the definition of a prime number. But you overlooked the purpose of this thread. The original question was : [QUOTE=davar55;99304]Can you define prime numbers over the non-negative integers without any explicit reference to 0 or 1 or 2 or any other specific integer?[/QUOTE] |
[QUOTE=Zeta-Flux;99599]Paul,
Using x/x would necessitate x\neq 0.[/QUOTE]Correct, and I should have stated that fact in the form "for values of x where x/x is defined". Thanks for drawing it to my attention. |
The purpose behind the formulation of this admittedly kind of
arbitrary question was to try to come up with an alternate, nonarbitrary explanation for why 1 isn't prime (alternate to the fundamental theorem of arithmetic's desirable simplicity). After all, a typical definition of primality in the natural numbers uses 1 twice: ( n is prime iff n>1 and a|n implies a=n or a=1 ) which begs the question. But my version of the definition probably still does too: Among the non-negative integers, n is prime iff ((n=ab IMPLIES (n=a OR n=b)) AND NOT (n*n=n)). This excludes 1 (and 0) from primality by using a trivial property (n*n=n) shared only by 1 and 0, without explicitly mentioning 1 or "unit". So by this definition, 1 is not prime. But as simple as it may be, it's still a bit arbitrary to put this into the definition, isn't it? Yet this is all I was getting at when posing the question. |
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