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-   -   Factoring humongous Cunningham numbers (https://www.mersenneforum.org/showthread.php?t=5722)

FactorEyes 2009-08-26 13:46

[QUOTE=Batalov;187439]I'd say let's get their count under 1000 and then suddenly stop.
[/QUOTE]

Just leave all the quartics and sextics, except for those with remaining composite no more than 10 digits smaller than the SNFS difficulty. And the number of composites remaining should not be divisible by 11 or 13.

fivemack 2009-08-27 00:21

[QUOTE=FactorEyes;179045]
[CODE]5^298+2^298 162.5 208.3 Reserved by Tom Womack at 20080906003858; if that's you, click here to unreserve it
5^298+4^298 174.2 208.3 Reserved by Tom Womack at 20080906003909; if that's you, click here to unreserve it[/CODE]

:wink:
[/QUOTE]

Touché. Running them now (4 threads on i7 each, since 5pm on 23rd August) and should have factors before the first birthday of the reservation.

fivemack 2009-08-28 22:27

I hope that the obvious small change I have made to the reservation page meets with popular approval.

FactorEyes 2009-08-28 23:46

[QUOTE=fivemack;187865]I hope that the obvious small change I have made to the reservation page meets with popular approval.[/QUOTE]
Niiice.

You gonna take out that SNFS 239 by the death-before-dishonor method, or are you going to take the easy way out and GNFS the 123-digit remaining cofactor?

Batalov 2009-08-28 23:50

Could you actually bold-face the SNFS or the GNFS difficulty value (one of them... based on being south or north from say, a 0.69 ratio value) for the newcoming users? It's clear that it is going to be merely a decoration, but just to guide the eye?

[b]fivemack: done, except in dark green to make the page look tidier[/b]

fivemack 2009-08-29 08:23

[QUOTE=FactorEyes;187870]Niiice.

You gonna take out that SNFS 239 by the death-before-dishonor method, or are you going to take the easy way out and GNFS the 123-digit remaining cofactor?[/QUOTE]

I am not the kind to push beans uphill with my nose. GNFS result should be available on Tuesday.

Andi47 2009-08-29 08:31

[QUOTE=Batalov;187871]Could you actually bold-face the SNFS or the GNFS difficulty value (one of them... based on being south or north from say, a 0.69 ratio value) for the newcoming users? It's clear that it is going to be merely a decoration, but just to guide the eye?

[b]fivemack: done, except in dark green to make the page look tidier[/b][/QUOTE]

Nice (but maybe a somewhat lighter green might be better - on some screens you have to look twice to see the contrast). And "xy days ago" looks much better than "a*10^b seconds ago". :smile:

fivemack 2009-08-29 08:41

[QUOTE=Andi47;187920]Nice (but maybe a somewhat lighter green might be better - on some screens you have to look twice to see the contrast). And "xy days ago" looks much better than "a*10^b seconds ago". :smile:[/QUOTE]

If someone is committing to a calculation that takes at least 24 hours, I don't think having to look twice to see what colour some number is counts as an onerous burden. If they can't see it on the screen it's clearly there in the HTML.

Andi47 2009-08-29 09:09

[QUOTE=fivemack;187925]If someone is committing to a calculation that takes at least 24 hours, I don't think having to look twice to see what colour some number is counts as an onerous burden. If they can't see it on the screen it's clearly there in the HTML.[/QUOTE]

OK, you're right.
BTW: "show reserved" - nice new feature.

Btw:
[code]10^191-7^191 151.4 191.0 [B]Reserved by Justin Card [COLOR="Red"]514.2 days ago[/COLOR][/B][/code]

Hmmmm.....

Andi47 2009-08-29 15:13

SNFS-193 in range for home computing?
 
Do I get this right, a difficulty-193-SNFS would take approx. as long as a 193*0.69 = 133-digit GNFS and thus would be in range for home computing?

If yes, I'd do 7^247+2^247; did I get the parameters approximately right?

[code]n: 3621230091357845376082358247365411609563071121050124332909068783146507904405019265661979402574439761951230992780105585919544323755259152887662499358178427511
c6: 1
c5: -1
c4: -5
c3: 4
c2: 6
c1: -3
c0: -1
Y1: 5976303958948914397184
Y0: -129934811447123020117447023605393
rlim: 33554431
alim: 33554431
lpbr: 28
lpba: 28
mfbr: 56
mfba: 56
rlambda: 2.6
alambda: 2.6
skew: 1
type: snfs[/code]

Which siever? 13e? 14e?
Edit: How many relations would that factorization need?

fivemack 2009-08-29 15:49

General rule for siever choice: if you get less than 2000 relations from a range of 1000 Q, use a bigger siever; if you get more than 6000 use a smaller siever.

General rule for relation counting: 0.1 * 2 ^ large prime bound


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