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-   -   Factoring humongous Cunningham numbers (https://www.mersenneforum.org/showthread.php?t=5722)

xilman 2009-02-10 19:58

[QUOTE=Batalov;162386]Tom must have one more cracked number hidden in his logs. He's got 107.[/QUOTE]Thanks for drawing it to my attention. Tom and I will try to discover the reason for the discrepancy.

There are still two "Anonymous" factorers in the list --- people who submitted factors to Tom but failed to leave any identifying information.


Paul

fivemack 2009-02-10 23:12

My logs contain
[code]

submitted factor 1692172982990093577812378437461931275624189112039 for 158144801129823105589177415267\
000105375446003633917659596480080273251444288727711939256263402156878412021305775219894362687437 (10^\
179+7^179) at 20090205111453
line removed/changed was 1581448011298231055891774152670001053754460036339176595964800802732514442887\
27711939256263402156878412021305775219894362687437:10^179+7^179:125.2:179.0:Andreas Tete:200901122314\
32:*emailredacted*:3837

[/code]

which does not correspond to an entry in xilman's table

xilman 2009-02-11 07:50

[QUOTE=fivemack;162398]My logs contain
[code]

submitted factor 1692172982990093577812378437461931275624189112039 for 158144801129823105589177415267\
000105375446003633917659596480080273251444288727711939256263402156878412021305775219894362687437 (10^\
179+7^179) at 20090205111453
line removed/changed was 1581448011298231055891774152670001053754460036339176595964800802732514442887\
27711939256263402156878412021305775219894362687437:10^179+7^179:125.2:179.0:Andreas Tete:200901122314\
32:*emailredacted*:3837

[/code]

which does not correspond to an entry in xilman's table[/QUOTE]Thanks. it will appear in the next update.


Paul

R.D. Silverman 2009-02-11 11:57

[QUOTE=xilman;162433]Thanks. it will appear in the next update.


Paul[/QUOTE]

The entry for 11,5,142+ seems to be missing as well.

Yamato 2009-03-15 10:21

10^197 - 9^197 is complete now:

[CODE]GMP-ECM 6.2.1 [powered by GMP 4.2.3] [ECM]
Input number is 751369216077158891503499854080642934669333107209800321633357791586209840929930047986384170010936023452474336728406674603200144240762175763959624680987220654224198173933638244111 (177 digits)
Using B1=11000000, B2=35133391030, polynomial Dickson(12), sigma=892337128
Step 1 took 57576ms
Step 2 took 20261ms
********** Factor found in step 2: 46409318416885028214841105038595360168439359
Found probable prime factor of 44 digits: 46409318416885028214841105038595360168439359
Probable prime cofactor 16190050655943040727316410478485425369930717176514453490269187669666230190327363671908899114874662388298260908413045713054746471105329 has 134 digits[/CODE]

FactorEyes 2009-03-20 14:51

Quarter days -- excellent for ECM
 
Looks as if the vernal equinox worked some magic.

P47 = 52556953778328070679456721807216441990292125691 finishes 11^193-10^193:

[CODE]Using B1=43000000, B2=240490660426, polynomial Dickson(12), sigma=671236552
Step 1 took 145369ms
Step 2 took 57571ms
********** Factor found in step 2: 52556953778328070679456721807216441990292125691
Found probable prime factor of 47 digits: 52556953778328070679456721807216441990292125691
Probable prime cofactor ((((11^193-10^193)/3089)/2207441338980923696929)/10369718194979776429937347002252683)/52556953778328070679456721807216441990292125691 has 96 digits
[/CODE]

xilman 2009-04-07 15:12

Update
 
Another update has just been posted.

There are now 85 composites in the tables


Paul

xilman 2009-04-07 15:19

[QUOTE=R.D. Silverman;162450]The entry for 11,5,142+ seems to be missing as well.[/QUOTE]Does anyone have the factorization of the C113, and know who first found it by which means? I don't seem to be able to find it.


Paul

Batalov 2009-04-18 19:53

[quote=Batalov;169251]I am pretty much done with 11+2,199 though. These are my two liabilities (and 3+2,494).[/quote]
It's a three-fer. Oh, how I am getting use to these 3-way splits now.

c207 = p58.p70.p79

bdodson 2009-04-19 01:55

[QUOTE=Batalov;169779]It's a three-fer. Oh, how I am getting use to these 3-way splits now.

c207 = p58.p70.p79[/QUOTE]

Yes, but 5,362+ c241 = prp68 * prp83 * prp90 was a better split! -bd

Batalov 2009-05-01 21:09

I can see that Ben[sup]2[/sup] is viciously hacking up the shrinking list.
The end is near!
The end is near! :smile:

(...and Paul knows it)


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