![]() |
A Counter example, anyone?
I may be wrong but I feel it may be difficult to cite a counter to the following:
Let N = P1P2P3 be a three factor composite number. The necessary & sufficient condition for N to be a pseudo-prime is that atleast one of the following should be an integer: ( P1 - 1)(N - 1)/(P2 -1)(P3-1), (P2-1)(N - 1)/(P1 -1)(P3 - 1) or (P3 - 1)(N -1)/(P1 -1)(P2 -1) A.K. Devaraj |
Integer !=> Pseudoprime
Double check this, but if we take 42 = 2 x 3 x 7.
Then (7-1) x (42-1) / ((2-1) x (3-1)) = 6 x 41 / 2 = 123 is an integer. However there does not exist a whole number a such that a^41 = 1 (mod 42) (a != 1 mod 42) |
[QUOTE=Dougy]Double check this, but if we take 42 = 2 x 3 x 7.
Then (7-1) x (42-1) / ((2-1) x (3-1)) = 6 x 41 / 2 = 123 is an integer. However there does not exist a whole number a such that a^41 = 1 (mod 42) (a != 1 mod 42)[/QUOTE] I should have specified the Ps as odd prime numbers;now I am not sure u will be able to cite a counter example. A.K. Devaraj |
[QUOTE=devarajkandadai] Let N = P1P2P3 be a three factor composite number.
The necessary & sufficient condition for N to be a pseudo-prime is that atleast one of the following should be an integer: ( P1 - 1)(N - 1)/(P2 -1)(P3-1), (P2-1)(N - 1)/(P1 -1)(P3 - 1) or (P3 - 1)(N -1)/(P1 -1)(P2 -1) [/QUOTE] It seems to work only in one direction (which is a particular case of your previous conjecture), i.e., if N is pseudo-prime then at least one (actually, all three) of the specified fractions is integer. But there are such non-pseudoprime N for which at least one of the fractions is integer. The smallest counterexamples: 105 = 3*5*7 165 = 3*5*11 195 = 3*5*13 |
[QUOTE=maxal]It seems to work only in one direction (which is a particular case of your previous conjecture), i.e., if N is pseudo-prime then at least one (actually, all three) of the specified fractions is integer.
But there are such non-pseudoprime N for which at least one of the fractions is integer. The smallest counterexamples: 105 = 3*5*7 165 = 3*5*11 195 = 3*5*13[/QUOTE] :rolleyes: There are two types of pseudo-primes viz 1) Fermat pseudo-primes and 2) Carmichael numbers. Kindly clarify which are you referring too. :question: :confused: Mally :coffee: |
[QUOTE=mfgoode]:rolleyes:
There are two types of pseudo-primes viz 1) Fermat pseudo-primes and 2) Carmichael numbers. Kindly clarify which are you referring too. :question: :confused: [/QUOTE] Either one. The quoted counterexamples are neither Fermat pseudoprimes, nor Carmichael numbers. |
A Counter example anyone?
[QUOTE=maxal]Either one. The quoted counterexamples are neither Fermat pseudoprimes, nor Carmichael numbers.[/QUOTE]
:unsure: Thank you maxal . Could you please elaborate the distinction between them and the no.s. you have derived as Im a bit confused :sad: Mally :coffee: |
[QUOTE=mfgoode]
Could you please elaborate the distinction between them[/QUOTE]See [url]http://mathworld.wolfram.com/FermatPseudoprime.html[/url] and [url]http://mathworld.wolfram.com/CarmichaelNumber.html[/url] [QUOTE=mfgoode]and the no.s. you have derived[/QUOTE]What's "no.s." ? |
[QUOTE=maxal]
What's "no.s." ?[/QUOTE] Numbers? (abbreviation). |
A Counter example anyone?
[QUOTE=maxal]Either one. The quoted counterexamples are neither Fermat pseudoprimes, nor Carmichael numbers.[/QUOTE]
:smile: Yes 99.94. This abbr. is widely used in this part of the world. Thank you once again maxal. The no.s you have derived evidently satisfy at least one of Devraj's eqn.s ( abbr.-equations). [Quote] Either one. The quoted counterexamples are neither Fermat pseudoprimes, nor Carmichael numbers.[/UNQUOTE]' maxal. :unsure: If you have ruled these two sets out then what category do the numbers 105 ,165,195 etc. fall under? :question: Thank you Mally :coffee: |
[QUOTE=mfgoode]
[Quote=maxal]Either one. The quoted counterexamples are neither Fermat pseudoprimes, nor Carmichael numbers.[/QUOTE] If you have ruled these two sets out then what category do the numbers 105 ,165,195 etc. fall under? :question: [/QUOTE] These numbers are not pseudoprimes (neither "Fermat pseudoprimes", nor "Carmichael numbers") for which at least one of Devaraj's fractions is integer. (I think I've already said that). |
| All times are UTC. The time now is 11:21. |
Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.