Not Ransomware Decryption
 

In generale se N=(6*a+1)*(6*b+1)

In particolare se viene risolto il problema della fattorizzazione per questo caso viene risolta per tutti i numeri



Allora

1) Se a è nella forma a=3*n+1

allora

[[[2*((N-1)/6)^2+((N-1)/6)] mod N]+5]/8=X



2) Se a è nella forma a=3*n+2

allora

[[[2*((N-1)/6)^2+((N-1)/6)] mod N]+4]/14=X



3) Se a è nella forma a=3*n

allora

[[[2*((N-1)/6)^2+((N-1)/6)] mod N]+0]/2=X



In particolare se viene risolto il problema della fattorizzazione per uno di questi tre casi viene risolta per tutti i numeri.



Concentriamoci sulla 1) ed in particolare con b nella forma b=3*m , anche in questo caso se risolviamo per b=3*m risolviamo anche per gli altri due casi.



In questa forma se



[[[2*((N-1)/6)^2+((N-1)/6)] mod N]+5]/8=X



allora



[[[2*((H-1)/6)^2+((H-1)/6)] mod H]+5]/8=X+(6*a+1)



dove H=N+18*(6*a+1)



quindi date queste tre:



4)
a=3*n+1 ; m =3*k , X=54*k*n+21*k+n+1

5)
a=3*n+1 ; m =3*k+1 , X=54*k*n+21*k+19*n+8

6)
a=3*n+1 ; m =3*k+2 , X=54*k*n+21*k+37*n+15

allora avremo la fattorizzazione

in questo modo:

4)
X=54*k*n+21*k+n+1 , X+(18*n+7)=54*k*n+21*k+19*n+8

5)
X=54*k*n+21*k+19*n+8 , X+(18*n+7)=54*k*n+21*k+37*n+15

6)
X=54*k*n+21*k+37*n+15 , X+(18*n+7)=54*(k+1)*n+21*(k+1)+n+1

[CODE]Va trarenyr fr A=(6*n+1)*(6*o+1)

Va cnegvpbyner fr ivrar evfbygb vy ceboyrzn qryyn snggbevmmnmvbar cre dhrfgb pnfb ivrar evfbygn cre ghggv v ahzrev

Nyyben

1) Fr n è aryyn sbezn n=3*a+1
nyyben
[[[2*((A-1)/6)^2+((A-1)/6)] zbq A]+5]/8=K

2) Fr n è aryyn sbezn n=3*a+2
nyyben
[[[2*((A-1)/6)^2+((A-1)/6)] zbq A]+4]/14=K

3) Fr n è aryyn sbezn n=3*a
nyyben
[[[2*((A-1)/6)^2+((A-1)/6)] zbq A]+0]/2=K

Va cnegvpbyner fr ivrar evfbygb vy ceboyrzn qryyn snggbevmmnmvbar cre hab qv dhrfgv ger pnfv ivrar evfbygn cre ghggv v ahzrev.

Pbapragevnzbpv fhyyn 1) rq va cnegvpbyner pba o aryyn sbezn o=3*z , napur va dhrfgb pnfb fr evfbyivnzb cre o=3*z evfbyivnzb napur cre tyv nygev qhr pnfv.

Va dhrfgn sbezn fr

[[[2*((A-1)/6)^2+((A-1)/6)] zbq A]+5]/8=K

nyyben

[[[2*((U-1)/6)^2+((U-1)/6)] zbq U]+5]/8=K+(6*n+1)

qbir U=A+18*(6*n+1)

dhvaqv qngr dhrfgr ger:

4) n=3*a+1 ; z =3*x , K=54*x*a+21*x+a+1

5) n=3*a+1 ; z =3*x+1 , K=54*x*a+21*x+19*a+8

6) n=3*a+1 ; z =3*x+2 , K=54*x*a+21*x+37*a+15
nyyben nierzb yn snggbevmmnmvbar
va dhrfgb zbqb:

4) K=54*x*a+21*x+a+1 , K+(18*a+7)=54*x*a+21*x+19*a+8

5) K=54*x*a+21*x+19*a+8 , K+(18*a+7)=54*x*a+21*x+37*a+15

6) K=54*x*a+21*x+37*a+15 , K+(18*a+7)=54*(x+1)*a+21*(x+1)+a+1[/CODE]

4)
[54*(k)*(n+1)+21*(k)+37*(n+1)+15 ]-X=-3+72*(n+1)+18*((3*(3*k)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k)+1)=N
Example
[54*(k)*(n+1)+21*(k)+37*(n+1)+15 ]-152=-3+72*(n+1)+18*((3*(3*k)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k)+1)=2725


5)
[54*(k+1)*(n+1)+21*(k+1)+(n+1)+1]-X=-3+72*(n+1)+18*((3*(3*k+1)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k+1)+1)=N
Example
[54*(k+1)*(n+1)+21*(k+1)+(n+1)+1]-8=-3+72*(n+1)+18*((3*(3*k+1)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k+1)+1)=133


6)
[54*(k+1)*(n+1)+21*(k+1)+19*(n+1)+8]-X=-3+72*(n+1)+18*((3*(3*k+2)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k+2)+1)=N
Example
[54*(k+1)*(n+1)+21*(k+1)+19*(n+1)+8]-15=-3+72*(n+1)+18*((3*(3*k+2)-2*(3*n+1)-1)/3) , (18*n+7)*(6*3*(3*k+2)+1)=259




Example of factoring for 6)


solve [54*(k+1)*(n+1)+21*(k+1)+19*(n+1)+8]-X-J=18*x , (18*n+7)*(6*3*(3*k+2)+1)=N,k,x

-18*7*J+25*N-126*X+6377=0

-18*7*(51+18*j)+25*N-126*X+6377=0

Example N=259 -> X=15

-18*7*(51+18*j)+25*259-126*15+6377=0
-> j=2 -> J=87

solve [54*(k+1)*(n+1)+21*(k+1)+19*(n+1)+8]-15-87=18*x , (18*n+7)*(6*3*(3*k+2)+1)=259,k,x

-> x=n*(36*n-23)/(18*n+7)
-> (36*n-23)-2*(18*n+7)=-37
-> GCD(37,133)!=7
-> n=0

Where are the factors for your other thread?
[url]https://mersenneforum.org/showthread.php?t=25821[/url]

Are you just going to abandon it and pretend it didn't happen? Or will you admit defeat?

[QUOTE=retina;555433]Where are the factors for your other thread?
[URL]https://mersenneforum.org/showthread.php?t=25821[/URL]

Are you just going to abandon it and pretend it didn't happen? Or will you admit defeat?[/QUOTE]


I like theory more than practice,
maybe one day I will

[QUOTE=Alberico Lepore;555437]I like theory more than practice,[/QUOTE]But your posts above have no theory at all. They are all just random manipulations where you 'practice' with 2 and 3 digit numbers.

[QUOTE=retina;555438]But your posts above have no theory at all. They are all just random manipulations where you 'practice' with 2 and 3 digit numbers.[/QUOTE]


3 digits


[url]https://www.wolframalpha.com/input/?i=solve+%5B54*%28k%2B1%29*%28n%2B1%29%2B21*%28k%2B1%29%2B19*%28n%2B1%29%2B8%5D-15-j%3D18*%28%283*%283*k%2B2%29%29-2*%283*n%2B1%29-1%29%2F3+%2C+%2818*n%2B7%29*%286*3*%283*k%2B2%29%2B1%29%3D259[/url]

[QUOTE=Alberico Lepore;555463]3 digits[/QUOTE]

You promised [URL="https://mersenneforum.org/showthread.php?p=554937#post554937"]in this thread exchange[/URL] that you'd leave if a valid reason was given for why we don't want you wasting our time.

Posted 2020-08-25, 16:42 AST:
[QUOTE=Alberico Lepore]@AdminGroup
however I understand
you are chasing me
it is your home and therefore I accept it
I will not write more unless directly called into question[/QUOTE]

But, then sometime later, you edited the thread, deleting your commitment.

Perhaps a SuperMod could ban this child for lying.

[QUOTE=chalsall;555465]You promised [URL="https://mersenneforum.org/showthread.php?p=554937#post554937"]in this thread exchange[/URL] that you'd leave if a valid reason was given for why we don't want you wasting our time.

Posted 2020-08-25, 16:42 AST:


But, then sometime later, you edited the thread, deleting your commitment.

Perhaps a SuperMod could ban this child for lying.[/QUOTE]
I am very tempted.

[QUOTE=retina;555438]But your posts above have no theory at all. They are all just random manipulations where you 'practice' with 2 and 3 digit numbers.[/QUOTE]

I've factored 18 digits number, but I need help optimizing the algorithm.

[url]https://mersenneforum.org/showthread.php?p=556028#post556028[/url]

[QUOTE=Alberico Lepore;556029]I need help...[/QUOTE]

Seconded...

[QUOTE=Alberico Lepore;556029]I've factored 18 digits number, but I need help optimizing the algorithm.[/QUOTE]
Try a 50 digit then 200 digit number. Optimize the math and the programming. Try your own hand at it first for a while. Then report the steps that you have taken.