August 2020
 

[url]http://www.research.ibm.com/haifa/ponderthis/challenges/August2020.html[/url]

For my understanding:

„(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“

(0,1,2) can result in the position (0,0,1), too?

[QUOTE=Dieter;552327]For my understanding:

„(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“

(0,1,2) can result in the position (0,0,1), too?[/QUOTE]

You are correct however (0,0,1) is also loosing

[QUOTE=Dieter;552327](0,1,2) can result in the position (0,0,1), too?[/QUOTE]
Yes, in two ways, either taking one from last two stacks, or taking 2 from the last stake, which goes to (0,1,0), but for the purpose of the game, (0,0,1) and (0,1,0) are the same. Stacks are commutative.
However, as tgan said, that is also losing, so the (0,1,2) is losing, you can't force a win.
P.S. I see they fixed it, adding the (0,0,1) to the list.