Constellations of multiples of 3 in this sequence
 

47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?

[QUOTE=enzocreti;537502]47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111
This is a sequence of numbers that reduced mod 41 are powers.
Are there infinitely many primes in this sequence?[/QUOTE]
Really? Whose power is 6? (i.e. .47 (mod 41))
:dnftt:

[QUOTE=enzocreti;537502]47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?[/QUOTE]

Of course!!! By [URL="Dirichlet's theorem on arithmetic progressions"]Dirichlet's theorem on arithmetic progressions[/URL], there are infinitely many primes = 4 mod 41, thus there are infinitely many such primes.

[QUOTE=enzocreti;537502]47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?[/QUOTE]

Wait!!! 47%41 = 6, and 6 is not perfect power....:poop::poop: