![]() |
roots of cubics
Hi,
say a cubic equation intersects the y-axis at a point where it's derivative is 0 and also intersects the y-axis at one other point (so it touches the y-axis twice), wouldn't it have to have one root that isn't real? Will |
[QUOTE=wildrabbitt;526574]Hi,
say a cubic equation intersects the y-axis at a point where it's derivative is 0 and also intersects the y-axis at one other point (so it touches the y-axis twice), wouldn't it have to have one root that isn't real? Will[/QUOTE] If you mean: y = f(x) where f is a cubic polynomial: IMPOSSIBLE. It is an elementary exercise to see why. There are two different reasons. |
[QUOTE=wildrabbitt;526574]Hi,
say a cubic equation intersects the y-axis at a point where it's derivative is 0 and also intersects the y-axis at one other point (so it touches the y-axis twice), wouldn't it have to have one root that isn't real? Will[/QUOTE] It is possible to have repeated roots of cubic equations. |
[QUOTE=wildrabbitt;526574]Hi,
say a cubic equation intersects the y-axis at a point where it's derivative is 0 and also intersects the y-axis at one other point (so it touches the y-axis twice), wouldn't it have to have one root that isn't real? Will[/QUOTE] No: if any polynomial has f(t)=0 and f'(t)=0 for the same t, that t is a multiple root of the polynomial (that is, the polynomial is divisible by (x-t)^2 ) |
[QUOTE=fivemack;526583]No: if any polynomial has f(t)=0 and f'(t)=0 for the same t, that t is a multiple root of the polynomial (that is, the polynomial is divisible by (x-t)^2 )[/QUOTE]
Sigh..... Bob runs screaming from the classroom...…...Has everyone forgotten basic algebra???? Reread what the OP wrote!! He said that the curve itself hits the y-axis twice......Once where its derivative is 0. i.e. he wants f(0) to have TWO DIFFERENT VALUES. This is not a function!!! [y = cubic polynomial in x] And, of course, a cubic can NEVER have a single imaginary root......Imaginary roots come in pairs! |
Bob-
It's pretty clear the OP meant x-axis, rather than y-axis. Your answer about imaginary (complex) roots always coming in pairs helps whether he typo'ed y-axis or not, though. |
[QUOTE=VBCurtis;526593]Bob-
It's pretty clear the OP meant x-axis, rather than y-axis. Your answer about imaginary (complex) roots always coming in pairs helps whether he typo'ed y-axis or not, though.[/QUOTE] I assume that people mean what they write. I assume that they proofread before posting. |
[QUOTE=R.D. Silverman;526594]I assume that people mean what they write. I assume that they proofread before posting.[/QUOTE]
Note that he wrote 'y-axis' three different times..... |
[QUOTE=R.D. Silverman;526595]Note that he wrote 'y-axis' three different times.....[/QUOTE]
This makes it even clearer that he meant 'the y=0 axis' (IE the X axis) |
[QUOTE=fivemack;526596]This makes it even clearer that he meant 'the y=0 axis' (IE the X axis)[/QUOTE]
I disagree. The content of the post speaks for itself. I assume that people mean what they write, especially when discussing a subject (such as mathematics) where it is possible to always use precise language. |
[QUOTE=R.D. Silverman;526594]I assume that people mean what they write. I assume that they proofread before posting.[/QUOTE]
Two bad assumptions, even around here. |
| All times are UTC. The time now is 18:00. |
Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.