[QUOTE=chalsall;515049]Yeah.

A friend of mine was in the Canadian military (Navy). The Captain of the ship had his First Officer keep a log book which recorded whatever sentence was the most amusing or poignant from the crew that day.

I would argue that [URL="https://mersenneforum.org/showpost.php?p=513966&postcount=177"]GP2[/URL]'s post would certainly qualify if such a log was kept here: "Theater comes in many different genres.[/QUOTE]


this is no entertainment you guys it is theater for my showdown of my supreme brilliance in mathematics, just wait for the prime confirmations then yall be stooped



dank

[QUOTE=samuel;515051]this is no entertainment you guys it is theater for my showdown of my supreme brilliance in mathematics, just wait for the prime confirmations then yall be stooped[/QUOTE]

Standing by.

[QUOTE=samuel;515029]i was trying to understand the first problem what the heck is lesbesgian nonmeasurable, the wikipedia article is making terminally no sense, is this math for real?[/QUOTE]
[QUOTE=xilman;515031]It most certainly is for real.[/QUOTE]
And just think. This is just to judge whether or not they let you in to get your graduate work. After they let you in there is more stuff to study.
[QUOTE=dcheuk;515034]Basically, if you take any set that fails the requirement of measurability then it is not Lebesgue measurable
......
Looks these definitions up if you don't understand them, and these concepts are relatively abstract for a high schooler tbh. Don't beat it on yourself if you don't get it (not trying to be offensive here). :smile:[/QUOTE]
[QUOTE=samuel;515040]i still dont get that no
........
well anyway when my numbers are prime especially both of them turns out to be i will be invincible just you see[/QUOTE]I told you, you have been only in the the swimming pool and there are lakes and oceans of math out there. Right now you might be able to touch the bottom and even swim a length under the water. But there are places vastly deeper than you have imagined before. You will tire out before you can swim from one side to the other.
[QUOTE=samuel;515051]my supreme brilliance in mathematics, just wait for the prime confirmations then yall be stooped[/QUOTE]To use another water analogy. You are big minnow in a small pond. Here on this forum there are titans swimming out of sight or just showing the tip of their size. One of the people who has replied to this thread has a wikipedia entry, a type/class of number named for them, an Erdos number of 2, their work has been cited over 1100 times, has doctorate from Oxford, among other things.

You still have much to learn in math. The sooner that you learn that the better. In this forum you have access to brilliant minds. Don't cheese them off and they will be more willing to help you.

[QUOTE=Uncwilly;515066]One of the people who has replied to this thread has a wikipedia entry,[...][/QUOTE]

After some googling, imagine my surprise to learn our own Paul Underwood was formerly a professional footballer. Cool! [url]https://en.wikipedia.org/wiki/Paul_Underwood[/url]

(or was that list all about one person?)

[QUOTE=VBCurtis;515080]After some googling, imagine my surprise to learn our own Paul Underwood was formerly a professional footballer. Cool! [url]https://en.wikipedia.org/wiki/Paul_Underwood[/url]

(or was that list all about one person?)[/QUOTE][url=https://en.wikipedia.org/wiki/retina]Me too[/url]. I'm soooo famous, 76 citations, 79368 bytes. :razz:

[QUOTE=VBCurtis;515080]After some googling, imagine my surprise to learn our own Paul Underwood was formerly a professional footballer. Cool! [url]https://en.wikipedia.org/wiki/Paul_Underwood[/url]

(or was that list all about one person?)[/QUOTE]

:lol: Not me, nor are the obituaries about me true.

It is [url]https://en.wikipedia.org/wiki/Paul_Leyland[/url]

[QUOTE=paulunderwood;515093]:lol: Not me, nor are the obituaries about me true.[/QUOTE]

You mean that the reports of your death are greatly exaggerated? I'm shocked. FAKE NEWS!

[QUOTE=samuel;515032]well the wikipedia article is making no sense and mentions probability, is this statistics? how is it math if the entire page contains little to no math symbols?[/QUOTE]Ok, so your speciality appears to be number theory. That's fair enough. Mathematics is far too broad a field for any one person to understand more than a tiny fraction of it.

Please prove the following theorem. It has been proved before but it will be interesting to see how you tackle it.

Let [I]x[/I], [I]y[/I], [I]a[/I] and [I]b[/I] all be integers, where [I]x[/I]>0, [I]y[/I]>0, [I]a[/I]>1 and [I]b[/I]>1. Prove that the only solution to

[I]x[sup]a[/sup][/I] - [I]y[sup]b[/sup][/I] = 1

is [I]x[/I] = 3, [I]a[/I] = 2, [I]y[/I] = 2, [I]b[/I] = 3.

You can easily check that 3[SUP]2[/SUP] - 2[SUP]3[/SUP] = 9 - 8 = 1

Just an update, 1 day 20 hours left for [M]88680457[/M] on CUDALucas!

[QUOTE=xilman;515101]

Let [I]x[/I], [I]y[/I], [I]a[/I] and [I]b[/I] all be integers, where [I]x[/I]>0, [I]y[/I]>0, [I]a[/I]>1 and [I]b[/I]>1. Prove that the only solution to

[I]x[sup]a[/sup][/I] - [I]y[sup]b[/sup][/I] = 1

is [I]x[/I] = 3, [I]a[/I] = 2, [I]y[/I] = 2, [I]b[/I] = 3.

You can easily check that 3[SUP]2[/SUP] - 2[SUP]3[/SUP] = 9 - 8 = 1[/QUOTE]

This might be embarrassing but at first this doesn't look that bad, but then I spent an hour attempting to prove it using analysis and ring theory but to no avail. I should probably go back to learning number theory ... :picard:

[QUOTE=VBCurtis;515080]After some googling, imagine my surprise to learn our own Paul Underwood was formerly a professional footballer. Cool! [URL]https://en.wikipedia.org/wiki/Paul_Underwood[/URL]

(or was that list all about one person?)[/QUOTE]


Just an off topic.
When I moved to UK I went to leave in Irthlingborough where on Sunday mornings I used to go to the car boot located at the Rushden & Diamonds Football Club car park, work office was nearby too, Ford Garage on the roundabout where I bought my cars (still best client there.lol).
Last year when I left Irthling the stadium was being demolish, nowadays it should already be down.... Anyway, Paul Underwood I met is probably 5 ft 11 in (1.80 m) tall and I have a witness.

[QUOTE]Just an update, 1 day 20 hours left for [URL="https://www.mersenne.org/report_exponent/?exp_lo=88680457&full=1"]88680457[/URL] on CUDALucas![/QUOTE]


GREAT! 1 day 20 hours left count down to me being creditted for finding the formula that everyone cant find!!!



[QUOTE=xilman;515101]Ok, so your speciality appears to be number theory. That's fair enough. Mathematics is far too broad a field for any one person to understand more than a tiny fraction of it.

Please prove the following theorem. It has been proved before but it will be interesting to see how you tackle it.

Let [I]x[/I], [I]y[/I], [I]a[/I] and [I]b[/I] all be integers, where [I]x[/I]>0, [I]y[/I]>0, [I]a[/I]>1 and [I]b[/I]>1. Prove that the only solution to

[I]x[sup]a[/sup][/I] - [I]y[sup]b[/sup][/I] = 1

is [I]x[/I] = 3, [I]a[/I] = 2, [I]y[/I] = 2, [I]b[/I] = 3.

You can easily check that 3[SUP]2[/SUP] - 2[SUP]3[/SUP] = 9 - 8 = 1[/QUOTE]


x^a-y^b=1 ----> x^a=1+y^b ------->x=(1+y^b)^(1/a)




didn't you already answered your question? that is the ONLY solution.