Product of the factorials of the digits of some primes
 

30241 is an example of prime such that 3!*0!*2!*4!*1!+1=17^2.

up to primes 10^9 i found that if a prime with this property starts with digit 6, then the square of always 161^2 . why?

[QUOTE=enzocreti;513976]30241 is an example of prime such that 3!*0!*2!*4!*1!+1=17^2.

up to primes 10^9 i found that if a prime with this property starts with digit 6, then the square of always 161^2 . why?[/QUOTE]

Are you familiar with the concept of signal to noise?

Sorry, that was a rhetorical question. I just needed to yell at someone for being stupid. Nothing personal.

[QUOTE=chalsall;513977]Are you familiar with the concept of signal to noise?

Sorry, that was a rhetorical question. I just needed to yell at someone for being stupid. Nothing personal.[/QUOTE]

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primes
 

as you can see all the primes which start with digit 6 ...The product of the factorials of their digits plus one is always 161^2 why is it not possible another square?

[QUOTE=enzocreti;513980]...why is it not possible another square?[/QUOTE]

You have presented your theorem. Run the empirical to see if it stands.