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is this a demonstrable formula?: (Extension of the independent variable)
Good morning,
is this a demonstrable formula?: (Extension of the independent variable) this formula has found prime numbers of different value A=((n*n)*99)/2 B=sqrt(A) C=sqrt(A)-1 In The Code .Py "B=Func" "C=Func-1" "N= n+1" [B]For n = 1 to 10000[/B] N=1229 prime numbers Func=997 prime numbers Func-1=982 prime numbers TOTAL PRIME NUMBERS OF DIFFERENT VALUE = 3208-N=1979 [B]For n = 1 to 100000[/B] N=9592 prime numbers Func=8052 prime numbers Func-1=8131prime numbers TOTAL PRIME NUMBERS OF DIFFERENT VALUE = 25775-N=16183 etc... [CODE] aa=1 ii=1 i2=0 GG=0 FF=0 VV =0 e = 0 AA=0 c = 1 a =3 bb=0 dd=0 I=1 II=1 III=1 i=1 i1=0 b=0 p=1 equTwo=0 equTwoo=0 equTwooo=0 mod=0 equ=0 moda=0 modaa=0 print('Helloword \n\n'); bb=input('Inserire numero: ') while p<=bb: equTwo= ((p*p)*99)//2 equTwoo=((equTwo**(1/2.0))//1) equTwooo=equTwoo-1 print(' N= ---->' , p) print(' FUNC= ---->' , equTwoo) print(' Func-1=---->', equTwooo) while I<=p: I=I*1 I=I+1 if p==I : print(' P is prime -----', p) AA=AA+1 break if p%I==0 : break while II<=equTwoo: II=II*1 II=II+1 if equTwoo==II : print(' Func is prime -----', equTwoo) modaa=modaa+1 break if equTwoo%II==0 : break while III<=equTwooo: III=III*1 III=III+1 if equTwooo==III : print(' FUNC-1 is prime -----', equTwooo) moda=moda+1 break if equTwooo%III==0 : break p=p+1 aa=aa+1 I=1 II=1 III=1 print('\n\n\nTOTALE NUMERI P TROVATI : ' , AA) print('\n\n\nTOTALE NUMERI Func TROVATI : ',modaa) print('\n\n\nTOTALE NUMERI FUNC-1 TROVATI : ',moda) [/CODE] |
[QUOTE=Godzilla;506310]Good morning,
is this a demonstrable formula? A=((n*n)*99)/2 B=sqrt(A) C=sqrt(A)-1 [/QUOTE] Yes, this is demonstrable formula. And so is this -- A=((n*n)*98)/2 B=sqrt(A) [B]Can you take a wild guess what B equals to?[/B] We are trying to understand how much do you know (if anything at all)? :nick: |
[QUOTE=Batalov;506337]Yes, this is demonstrable formula.
And so is this -- A=((n*n)*98)/2 B=sqrt(A) [B]Can you take a wild guess what B equals to?[/B] We are trying to understand how much do you know (if anything at all)? :nick:[/QUOTE] With number 98 B= n*7 ? [B]--EDIT--[/B] n=88 >>> ((88*88)*99)//2 383328 >>> ((383328**(1/2.0))//1) 619.0 >>> 619 is prime and..I do not understand ... |
[QUOTE=Batalov;506337]Yes, this is demonstrable formula.
And so is this -- A=((n*n)*98)/2 B=sqrt(A) [B]Can you take a wild guess what B equals to?[/B] We are trying to understand how much do you know (if anything at all)? :nick:[/QUOTE] [QUOTE=Godzilla;506340]With number 98 B= n*7 ? [B]--EDIT--[/B] n=88 >>> ((88*88)*99)//2 383328 >>> ((383328**(1/2.0))//1) 619.0 >>> 619 is prime and..I do not understand ...[/QUOTE] 99 isn't 98. |
[QUOTE=Godzilla;506310][CODE]
aa=1 ii=1 i2=0 GG=0 FF=0 VV =0 e = 0 AA=0 c = 1 a =3 bb=0 dd=0 I=1 II=1 III=1 i=1 i1=0 b=0 p=1 equTwo=0 equTwoo=0 equTwooo=0 mod=0 equ=0 moda=0 modaa=0 print('Helloword \n\n'); bb=input('Inserire numero: ') while p<=bb: equTwo= ((p*p)*99)//2 equTwoo=((equTwo**(1/2.0))//1) equTwooo=equTwoo-1 print(' N= ---->' , p) print(' FUNC= ---->' , equTwoo) print(' Func-1=---->', equTwooo) while I<=p: I=I*1 I=I+1 if p==I : print(' P is prime -----', p) AA=AA+1 break if p%I==0 : break while II<=equTwoo: II=II*1 II=II+1 if equTwoo==II : print(' Func is prime -----', equTwoo) modaa=modaa+1 break if equTwoo%II==0 : break while III<=equTwooo: III=III*1 III=III+1 if equTwooo==III : print(' FUNC-1 is prime -----', equTwooo) moda=moda+1 break if equTwooo%III==0 : break p=p+1 aa=aa+1 I=1 II=1 III=1 print('\n\n\nTOTALE NUMERI P TROVATI : ' , AA) print('\n\n\nTOTALE NUMERI Func TROVATI : ',modaa) print('\n\n\nTOTALE NUMERI FUNC-1 TROVATI : ',moda) [/CODE][/QUOTE]This code is totally awesome :tu: Such beautiful variable naming :tu: Such consistent spacing and alignment :tu: Such excellent and useful comments :tu: Clearly so much effort expended to make it concise and easy to understand :tu: The work of a code god :tu: :bow: /sarc :no: Couldn't you at least try to make it [b]readable[/b]. Or even tell us what interpreter/language it is? |
@GRGreathouse could it be a new alghorithm?
@retina language is Python language, copy the code to a text file and save it with filename.py, open python and run it. |
[QUOTE=Godzilla;506340]With number 98 B= n*7 ?
and..I do not understand ...[/QUOTE] Ok, so you do understand some things. That is: squaring something and then taking a sqrt is a waste of time. But you [B]prefer [/B]to waste time (yours and others'). What is so difficult, then, in taking sqrt(99/2) ? It is a constant, if you take it with enough digits of precision you will be set for doing simply: [C]B = floor(n * 7.03562363973514433184) C = B - 1 [/C] Your function is a line through numbers. Granted, its slope is ugly, but so what. What makes you think that it will be better than most other functions to "generate primes"? For comparsion: [C]B = 2310*n+1 C = 2310*n-1[/C] will generate more primes than "A=sqrt(((n*n)*99)/2)". How do you arrive at your "wild and never before seen" "functions"? Do you just randomly press some buttons? |
[QUOTE=Batalov;506357]Ok, so you do understand some things. That is: squaring something and then taking a sqrt is a waste of time. But you [B]prefer [/B]to waste time (yours and others').
What is so difficult, then, in taking sqrt(99/2) ? It is a constant, if you take it with enough digits of precision you will be set for doing simply: [C]B = floor(n * 7.03562363973514433184) C = B - 1 [/C] Your function is a line through numbers. Granted, its slope is ugly, but so what. What makes you think that it will be better than most other functions to "generate primes"? For comparsion: [C]B = 2310*n+1 C = 2310*n-1[/C] will generate more primes than "A=sqrt(((n*n)*99)/2)". How do you arrive at your "wild and never before seen" "functions"? Do you just randomly press some buttons?[/QUOTE] I try with small tests with the electronic calculator and pen and paper, and later with the computer, if I do not understand I ask. |
[QUOTE=Godzilla;506356]@retina ... copy the code to a text file and save it with filename.py, open python and run it.[/QUOTE]With names like [u]equTwooo[/u] that ain't gonna happen. :no:
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[QUOTE=retina;506353]This code is totally awesome :tu:
Such beautiful variable naming :tu: Such consistent spacing and alignment :tu: Such excellent and useful comments :tu: Clearly so much effort expended to make it concise and easy to understand :tu: The work of a code god :tu: :bow: /sarc :no: Couldn't you at least try to make it [b]readable[/b]. Or even tell us what interpreter/language it is?[/QUOTE] Obligatory: |
what a strange math forum this is. People are always bickering. and when you ask something serious, no response, but BS always get answers.
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