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-   -   A vernacular 1051 digit probable prime (https://www.mersenneforum.org/showthread.php?t=23823)

enzocreti 2018-11-22 14:30

A vernacular 1051 digit probable prime
 
3511 is the largest known Wieferich prime.




(2^3510-1 +31*73*81)/(2*31*73*729) is a spectacular 1051 digit prp!!!

enzocreti 2018-11-22 14:46

Proven prime
 
Is it possible to say if it is actually prime?

paulunderwood 2018-11-22 14:57

[QUOTE=enzocreti;500742]Is it possible to say if it is actually prime?[/QUOTE]

Yes. :grin:

enzocreti 2018-11-22 14:58

how
 
how?

enzocreti 2018-11-22 15:00

form of the prime
 
the prime has a particular form...
2^3510-1 is divisible by 73 and 31
3511 is a Wieferich prime
81 and 729 are powers of 3

paulunderwood 2018-11-22 15:06

[QUOTE=enzocreti;500745]how?[/QUOTE]

Well, one can use Pari/GP's isprime() function given enough allocated RAM and runtime. Or use the newer ECPP capabilities of Pari/GP. Alternatively, run Primo. :smile:

enzocreti 2018-11-22 15:09

Even more spectalurar:
((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2 is also probable prime!!!

GP2 2018-11-22 15:13

[QUOTE=enzocreti;500742]Is it possible to say if it is actually prime?[/QUOTE]

Yes, it is.

For example, if you have a very recent version of PARI/GP (2.11 or higher), you can run something like:

[CODE]
default(parisizemax, 64000000)
cert = primecert((2^3510-1 +31*73*81)/(2*31*73*729));
s = primecertexport(cert, 1);
write("cert.out", s);
[/CODE]

I just did this and it took only a few minutes.

Why is this PRP spectacular? It's fairly small.

enzocreti 2018-11-22 15:17

((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2is a prime congruent to 1 mod 73

paulunderwood 2018-11-22 15:22

[QUOTE=enzocreti;500750]((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2is a prime congruent to 1 mod 73[/QUOTE]

"is a prime" -- have you proved that?

"congruent to 1 mod 73" -- so what?

enzocreti 2018-11-22 15:25

factordb
 
it is a probable prime for factordb, moreover it is 1 mod 73 as 2^3510-1


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