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A vernacular 1051 digit probable prime
3511 is the largest known Wieferich prime.
(2^3510-1 +31*73*81)/(2*31*73*729) is a spectacular 1051 digit prp!!! |
Proven prime
Is it possible to say if it is actually prime?
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[QUOTE=enzocreti;500742]Is it possible to say if it is actually prime?[/QUOTE]
Yes. :grin: |
how
how?
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form of the prime
the prime has a particular form...
2^3510-1 is divisible by 73 and 31 3511 is a Wieferich prime 81 and 729 are powers of 3 |
[QUOTE=enzocreti;500745]how?[/QUOTE]
Well, one can use Pari/GP's isprime() function given enough allocated RAM and runtime. Or use the newer ECPP capabilities of Pari/GP. Alternatively, run Primo. :smile: |
Even more spectalurar:
((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2 is also probable prime!!! |
[QUOTE=enzocreti;500742]Is it possible to say if it is actually prime?[/QUOTE]
Yes, it is. For example, if you have a very recent version of PARI/GP (2.11 or higher), you can run something like: [CODE] default(parisizemax, 64000000) cert = primecert((2^3510-1 +31*73*81)/(2*31*73*729)); s = primecertexport(cert, 1); write("cert.out", s); [/CODE] I just did this and it took only a few minutes. Why is this PRP spectacular? It's fairly small. |
((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2is a prime congruent to 1 mod 73
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[QUOTE=enzocreti;500750]((2^3510-1 +31*73*81)/(2*31*73*729)*9+1)/2is a prime congruent to 1 mod 73[/QUOTE]
"is a prime" -- have you proved that? "congruent to 1 mod 73" -- so what? |
factordb
it is a probable prime for factordb, moreover it is 1 mod 73 as 2^3510-1
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