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crossnumber #8
A challenging puzzle I found mentioned on [URL]https://blogs.ams.org/blogonmathblogs/[/URL] :
[URL]http://chalkdustmagazine.com/regulars/crossnumber/prize-crossnumber-issue-08/[/URL] |
[QUOTE=Till;499914]A challenging puzzle I found mentioned on [URL]https://blogs.ams.org/blogonmathblogs/[/URL] :
[URL]http://chalkdustmagazine.com/regulars/crossnumber/prize-crossnumber-issue-08/[/URL][/QUOTE] a few things. [SPOILER]9D,36A,20D,3D,4D,22D,8D,26D,23A,5D, and 6D have to all be 2 mod 5 and 6 mod 7 ( so 27 mod 35) 21A is 257 16D and 3A both show 18A<72, if different 18A<69 1A is surrounded by numbers that only have 2's and 3's as factors because n^2-1=(n-1)*(n+1) [/SPOILER] |
[QUOTE=science_man_88;499925]a few things.
[SPOILER]9D,36A,20D,3D,4D,22D,8D,26D,23A,5D, and 6D have to all be 2 mod 5 and 6 mod 7 ( so 27 mod 35) 21A is 257 16D and 3A both show 18A<72, if different 18A<69 1A is surrounded by numbers that only have 2's and 3's as factors because n^2-1=(n-1)*(n+1) [/SPOILER][/QUOTE] I found this one MUCH easier than one I did a few months ago....only took me a few hours off and on. Now lets hope I submitted the right sum 2 hints: 34A; Proth Numbers 14D: Triperfect number |
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