Chalkdust crossnumber 07
 

If anyone could give solutions to some of these problems, that would be much appreciated!:smile::bow:


[url]http://chalkdustmagazine.com/category/regulars/crossnumber/[/url]

Here are some answers or possible answers:

2 & 11:[CODE][SPOILER]153
370
371
407[/SPOILER][/CODE]

4 & 5: [SPOILER]136 <--> 244[/SPOILER]

7:[CODE][SPOILER]378
666
990[/SPOILER][/CODE]

24:[CODE][SPOILER]1634
8208
9474[/SPOILER][/CODE]

26: [SPOILER]736[/SPOILER]

29:[CODE][SPOILER]54748
92727
93084[/SPOILER][/CODE]

Edit: No leading zeroes.

13: [SPOILER]426[/SPOILER]
8: [SPOILER]426^6 = 5976646846618176[/SPOILER]
12: [SPOILER]426^5 = 14029687433376[/SPOILER]

17: [SPOILER]224[/SPOILER]

22: [SPOILER]427 - 630[/SPOILER]
10: [SPOILER]427^5 - 630^5[/SPOILER]

I've submitted my answer now.

For anyone looking to compare answers, the MD5 hash for the sum of my accross clues is e8938a2d47a3f3c420478335278eb2e9.

Another interesting point is that the answer is a semiprime equal to 5 * p16.

My answer matches your 5XP16

For MD5....I tried 3 different MD5 generators and got 3 different answers but 1 matched yours.

I think we match!!!

I have to acknowledge that my son helped a ton and had the "BIG" calculator.

[QUOTE=petrw1;487614]I have to acknowledge that my son helped a ton and had the "BIG" calculator.[/QUOTE]What's the "BIG" calculator? I used pari/gp for a few answers, is that what you mean?

[QUOTE=lavalamp;487457]... the MD5 hash is ... e8938a2d47a3f3c420478335278eb2e9.

... the answer is a semiprime equal to 5 * p16.[/QUOTE]So all I have to do is hash all 16 and 17 digit numbers of the form 5*p16 and I can get the answer. Should be a doddle. brb

[size=1]There are only 249,393,770,611,256 p16 numbers. Easy.[/size] :tu:

[QUOTE=lavalamp;487628]What's the "BIG" calculator? I used pari/gp for a few answers, is that what you mean?[/QUOTE]

Java with BigInteger.

[QUOTE=petrw1;487656]Java with BigInteger.[/QUOTE]Ah, no need for that. All of these fit well inside a 64 bit int, you can get 19 digits in those.

[QUOTE=retina;487636]So all I have to do is hash all 16 and 17 digit numbers of the form 5*p16 and I can get the answer. Should be a doddle. brb

[size=1]There are only 249,393,770,611,256 p16 numbers. Easy.[/size] :tu:[/QUOTE]Sadly do-able these days in a couple of hours with a 1080 Ti.

[QUOTE=lavalamp;487674]Ah, no need for that. All of these fit well inside a 64 bit int, you can get 19 digits in those.
[/QUOTE]

Yes, he mentioned that after he was done.