![]() |
Pseudo-Prime Bases
Hi all,
Is there a systematic method (other than brute force) to find a base whereby a given composite n will yield a false positive in FLT testing, other than n+1 and n-1 ? Does such a base exist for any given composite? Are such Bases finite in number? Thank you in advance.:smile: |
[QUOTE=a1call;475929]Does such a base exist for any given composite? [/QUOTE]
Excluding even numbers and powers of 3, the answer seem to be yes. |
Thank you for the insight axn.
Re: My 2nd question, well it certainly can't be infinite unless bases greater than n are considered. So a mute question I can see.:smile: |
Does "FLT testing" mean the Fermat probable-prime test? I'll assume this below, otherwise please clarify the term. :smile:
[QUOTE=a1call;475929]Is there a systematic method (other than brute force) to find a base whereby a given composite n will yield a false positive in FLT testing, other than n+1 and n-1 ?[/QUOTE] I don't know of one offhand, but I expect there is a method, at least if you have the factorization of n. [QUOTE=a1call;475929]Does such a base exist for any given composite?[/QUOTE] If [$$]n = p_1^{e_1}p_2^{e_2}\cdots p_k^{e_k}[/$$] (with p1 < p2 < ... < pk and all exponents positive integers) then there are [$$]\prod_{i=1}^k \gcd(p_i-1, n-1)[/$$] bases to which n is a pseudoprime. This fits axn's comment pretty well: it's easy to see that only prime powers could have the minimum 2 bases, and p - 1 divides p^e - 1 so only powers of 3 work. [QUOTE=a1call;475929]Are such Bases finite in number?[/QUOTE] As you pointed out, this question is moot -- there are only finitely many choices unless you count integers rather than integers mod n. |
| All times are UTC. The time now is 19:58. |
Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.