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-   -   A Sierpinski/Riesel-like problem (https://www.mersenneforum.org/showthread.php?t=21839)

sweety439 2018-01-10 19:15

[QUOTE=sweety439;477109]S8 has 4 k's remain: 256, 467, 1028, 1132.
S9 has 6 k's remain: 1039, 1627, 1801, 2007, 2036, 2287.
S11 has 2 k's remain: 195 and 237.
S13 has no k's remain.
R8 has 2 k's remain: 239 and 247.
R9 has no k's remain.
R11 has 5 k's remain: 201, 243, 851, 855, 856.
R13 has no k's remain.[/QUOTE]

Reserve them.

sweety439 2018-01-10 19:17

[QUOTE=sweety439;477175]Reserve them.[/QUOTE]

Found these (probable) primes:

(1627*9^2939+1)/4
(2007*9^3942+1)/8
(243*11^2384-1)/2
(856*11^2105-1)/5

Continue reserving...

MisterBitcoin 2018-01-14 10:43

[QUOTE=sweety439;477176]Found these (probable) primes:

(1627*9^2939+1)/4
(2007*9^3942+1)/8
(243*11^2384-1)/2
(856*11^2105-1)/5

Continue reserving...[/QUOTE]

Those are all proven by Edwin Hall. :smile:
Reserving (751*4^6615-1)/3, should take ~12K sec.

MisterBitcoin 2018-01-14 16:54

Canidate [URL="http://www.factordb.com/index.php?id=1100000000891891792&open=prime"](751*4^6615-1)/3[/URL], proven.

sweety439 2018-01-15 06:20

[QUOTE=MisterBitcoin;477520]Canidate [URL="http://www.factordb.com/index.php?id=1100000000891891792&open=prime"](751*4^6615-1)/3[/URL], proven.[/QUOTE]

Thanks!!!

You fully proved the 2nd and the 3rd conjecture for R4!!!

I think you can prove the primality for the probable primes in the post [URL="http://mersenneforum.org/showpost.php?p=476728&postcount=552"]#552[/URL] first. Some bases only need one primality proving, e.g. R17, it only needs the primality proving for the probable prime (29*17^4904-1)/4.

sweety439 2018-02-04 08:42

Reserve S93 and S117.

sweety439 2018-02-04 08:53

[QUOTE=sweety439;479228]Reserve S93 and S117.[/QUOTE]

Found 2 (probable) primes:

(11*117^1164+1)/4
(75*117^1428+1)/4

Current likely at n=2K, S93 has no (probable) primes found.

Continue to find...

sweety439 2018-02-04 13:48

[QUOTE=sweety439;479229]Found 2 (probable) primes:

(11*117^1164+1)/4
(75*117^1428+1)/4

Current likely at n=2K, S93 has no (probable) primes found.

Continue to find...[/QUOTE]

Found 2 (probable) primes:

(19*93^4362+1)/4
(43*93^2994+1)/4

S93 k=67, S93 k=87 and S117 k=59 are still remain (also the half GFN's, i.e. S93 k=93 and S117 k=117).

sweety439 2018-02-04 14:13

[QUOTE=sweety439;479239]Found 2 (probable) primes:

(19*93^4362+1)/4
(43*93^2994+1)/4

S93 k=67, S93 k=87 and S117 k=59 are still remain (also the half GFN's, i.e. S93 k=93 and S117 k=117).[/QUOTE]

No primes found for these k's, they are likely tested to n=8K.

sweety439 2018-02-04 14:14

Reserve R93 and R117.

sweety439 2018-02-11 06:50

[QUOTE=sweety439;479241]Reserve R93 and R117.[/QUOTE]

No (probable) primes found for R93 and R117, they are likely tested to n=8K.

Reserve R85 and R115.


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