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[QUOTE=Batalov;431065]In addition to what Charles wrote, infinitude of composite members of any sequence has nothing to do with the infinitude of prime members.
sm88, you need to start thinking at least about the basic properties of infinities: that is, (even for complementary sets, e.g. a set "A" and a set of all others "non-A"): - a sum of a finite set and and infinite set is an infinite set; - a sum of an infinite set and and infinite set is an infinite set, so - knowing that one subset is infinite (e.g. "non-A") gives you [B]no[/B] information about its complement's infinitude.[/QUOTE] okay thanks. , the local king of the idiots. |
For kicks and giggles, I found a larger triple set:
[URL="http://factordb.com/index.php?query=23660119537*2^18001-1"]23660119537*2^18001-1[/URL] = p (5430 digits) [URL="http://factordb.com/index.php?query=2^18002*70980358611-5"]3*23660119537*2^18002-5[/URL] = 6p-1, twin [URL="http://factordb.com/index.php?query=2^18002*70980358611-7"]3*23660119537*2^18002-7[/URL] = 6p+1, twin |
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