E=6
 

UID: Tha, M11021683 completed P-1, B1=250000, B2=5000000, E=6, We2: 1D1AB19A
UID: Tha, M11057201 completed P-1, B1=250000, B2=5000000, E=6, We2: 1E77B07F
UID: Tha, M11021789 completed P-1, B1=250000, B2=5000000, We2: 1D77B19F
UID: Tha, M11057401 completed P-1, B1=250000, B2=5000000, E=6, We2: 1E64B07D

What does E=6 mean and how come one test does omit it in its report?

[url]http://www.mersennewiki.org/index.php/Brent-Suyama_extension[/url]

[QUOTE=tha;368787]... and how come one test does omit it in its report?[/QUOTE]
At the time when the memory was allocated for stage 2, it was available in lower quantity compared with the other 3 cases/times. This can be due to the fact that other P95 workers, or other different windoze programs/applications/tasks were running in that particular moment, taking few more kilobytes of memory than usual, so that particular P95 worker didn't get enough memory for its BrSu exponents.

How about this:
[code](...)
4421*10^1297300-1 completed P-1, B1=50000, B2=575000, We8: 219CBB51
4421*10^1297432-1 completed P-1, B1=55000, B2=632500, E=4, We8: 21B64FBA
(...)
4421*10^1329820-1 completed P-1, B1=55000, B2=632500, E=4, We8: 22624EF6
4421*10^1329892-1 completed P-1, B1=55000, B2=646250, E=6, We8: 2288803D
(...)[/code]
I have assigned 3072MB to the second stage, and mprime reports using ~700MB, so why the E=x entries? This PC (laptop) has a total of 4GB of memory and operates under 64-bit Ubuntu 11.04. I am using single thread since two threads generate to much heat on this machine :smile:

[QUOTE=Cruelty;375940]< snip > and mprime reports using ~700MB[/QUOTE]Reports ... when? At start of stage 2, before Brent-Suyama was in progress?

[QUOTE=cheesehead;376019]Reports ... when? At start of stage 2[/QUOTE]

Is there any other time when P95/mprime reports memory usage?

I thought maybe Brent-Suyama issues bonus reports. Dunno because I don't have enough RAM to get an e=

[QUOTE=cheesehead;376019]Reports ... when? At start of stage 2, before Brent-Suyama was in progress?[/QUOTE]
At start of stage 2 - memory usage does not increase afterwards (I've checked it with system monitor).

Further observation shows that regardless of B1/B2 bounds automatically set by mprime/prime95, at the beginning of stage 2 I am getting "using 715MB of memory" output:
[code][Jul 14 09:26] Worker starting
[Jul 14 09:26] Setting affinity to run worker on logical CPU #1
[Jul 14 09:26] Optimal P-1 factoring of 4421*10^1568830-1 [B]using up to 3072MB of memory.[/B]
[Jul 14 09:26] Assuming no factors below 2^47 and 10 primality tests saved if a factor is found.
[Jul 14 09:26] Optimal bounds are B1=70000, B2=857500
[Jul 14 09:26] Chance of finding a factor is an estimated 1.84%
[Jul 14 09:26] Using FFT length 448K, Pass1=448, Pass2=1K
[Jul 14 09:27] 4421*10^1568830-1 stage 1 is 44.53% complete.
[Jul 14 09:30] 4421*10^1568830-1 stage 1 is 54.16% complete. Time: 153.014 sec.
[Jul 14 09:31] 4421*10^1568830-1 stage 1 is 63.80% complete. Time: 75.501 sec.
[Jul 14 09:32] 4421*10^1568830-1 stage 1 is 73.44% complete. Time: 74.519 sec.
[Jul 14 09:33] 4421*10^1568830-1 stage 1 is 83.08% complete. Time: 74.554 sec.
[Jul 14 09:35] 4421*10^1568830-1 stage 1 is 92.72% complete. Time: 74.376 sec.
[Jul 14 09:36] 4421*10^1568830-1 stage 1 complete. 116030 transforms. Time: 512.276 sec.
[Jul 14 09:36] Starting stage 1 GCD - please be patient.
[Jul 14 09:36] Stage 1 GCD complete. Time: 25.096 sec.
[Jul 14 09:36] [B]Using 715MB of memory.[/B] Processing 192 relative primes (0 of 192 already processed).
[Jul 14 09:38] 4421*10^1568830-1 stage 2 is 12.28% complete. Time: 108.361 sec.
[Jul 14 09:40] 4421*10^1568830-1 stage 2 is 31.01% complete. Time: 108.504 sec.
[Jul 14 09:42] 4421*10^1568830-1 stage 2 is 49.70% complete. Time: 110.384 sec.
[Jul 14 09:44] 4421*10^1568830-1 stage 2 is 68.38% complete. Time: 114.717 sec.
[Jul 14 09:45] 4421*10^1568830-1 stage 2 is 87.05% complete. Time: 113.768 sec.
[Jul 14 09:47] 4421*10^1568830-1 stage 2 complete. 113830 transforms. Time: 633.168 sec.
[Jul 14 09:47] Starting stage 2 GCD - please be patient.
[Jul 14 09:47] Stage 2 GCD complete. Time: 25.589 sec.
[Jul 14 09:47] 4421*10^1568830-1 completed P-1, B1=70000, B2=857500, E=6, We4: 28A81BA2[/code]

[QUOTE=Cruelty;378042]
[code][Jul 14 09:26] Assuming no factors below 2^47 and [B]10 primality tests[/B] saved if a factor is found.
[/code][/QUOTE]
As an aside: It is ok to do this when you just want to see what p95 would do, but for regular work, this is pointless to fool the software into doing P-1 when it is not profitable.

[QUOTE=axn;378043]As an aside: It is ok to do this when you just want to see what p95 would do, but for regular work, this is pointless to fool the software into doing P-1 when it is not profitable.[/QUOTE]
Doing P-1 work removes additional >2% (more than estimated 1.5-1.8%) candidates that I wouldn't be able to remove (during the same time) using current sieve software, and my laptop is not really well suited to perform LL tests (watching progress would be similarly exciting to watching a paint dry) :smile:

[QUOTE=Cruelty;378048]Doing P-1 work removes additional >2% (more than estimated 1.5-1.8%) candidates that I wouldn't be able to remove (during the same time) using current sieve software, and my laptop is not really well suited to perform LL tests (watching progress would be similarly exciting to watching a paint dry) :smile:[/QUOTE]

For every test saved by P-1 (1 in every 50 tries), the laptop would have cleared about 5 tests in the same time using LLR, wouldn't it?

[QUOTE=axn;378055]For every test saved by P-1 (1 in every 50 tries), the laptop would have cleared about 5 tests in the same time using LLR, wouldn't it?[/QUOTE]

Maybe, but like I said, I don't use this laptop for LL assignments.
Anyways: :direction: