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How much power am I really using?
I know what I have for a power supply in each system.
But if they all were at capacity my power bill for PCs alone would be the whole bill. Does anyone have a sense for how much power a PC typically daws? For example an i5-750 or an i5-3570, both OC'd 20%. Fan, CPU and RAM probably non stop but Monitor is almost always off, and hard drive too. No GPU. Or is there a device I can get to measure it? Thx |
[QUOTE=petrw1;361895]I know what I have for a power supply in each system.
But if they all were at capacity my power bill for PCs alone would be the whole bill. Does anyone have a sense for how much power a PC typically daws? For example an i5-750 or an i5-3570, both OC'd 20%. Fan, CPU and RAM probably non stop but Monitor is almost always off, and hard drive too. No GPU. Or is there a device I can get to measure it? Thx[/QUOTE] Kill-A-Watt for sure! :smile: |
[QUOTE=kracker;361896]Kill-A-Watt for sure! :smile:[/QUOTE]
I agree. You cannot measure the draw on a DC (direct current) feed without "being in the circuit". An AC (alternating current) feed *can* be measured without being in the circuit, so long as you know the frequency and the voltage being used. This is grade-school physics. |
[QUOTE=chalsall;361897]
You cannot measure the draw on a DC (direct current) feed without "being in the circuit". [/QUOTE] Hall effect sensors would disagree. |
[QUOTE=sdbardwick;361899]Hall effect sensors would disagree.[/QUOTE]
As always, I'm very happy to be corrected. I was arguing from the perspective of the instrumentation most of us have available to us. Perhaps that was short-sighted. A DC meter can only measure DC load when "in circuit". Most electricians carry around with them a device which can measure the number of amps being carried through a single wire carrying AC -- importantly without having to break the wire, but only when encircling a single current carrying wire -- when the device encircles the bundled wires it measures zero (as it should). Perhaps you could let us all know what hall effect sensors are available retail? I would sincerely be interested in knowing. |
[QUOTE=petrw1;361895]I know what I have for a power supply in each system.
But if they all were at capacity my power bill for PCs alone would be the whole bill. Does anyone have a sense for how much power a PC typically daws? For example an i5-750 or an i5-3570, both OC'd 20%. Fan, CPU and RAM probably non stop but Monitor is almost always off, and hard drive too. No GPU. Or is there a device I can get to measure it? Thx[/QUOTE] For a ballpark answer, take the CPU max TDP and add 10-20 watts for motherboard, RAM, fans, and PS inefficiency. |
[QUOTE=Mark Rose;361903]For a ballpark answer, take the CPU max TDP and add 20-30 watts for motherboard, RAM, fans, and PS inefficiency.[/QUOTE]
That's not a measurement. It's an estimate. A very important difference. |
[QUOTE=petrw1;361895]I know what I have for a power supply in each system.
But if they all were at capacity my power bill for PCs alone would be the whole bill. Does anyone have a sense for how much power a PC typically daws? For example an i5-750 or an i5-3570, both OC'd 20%. Fan, CPU and RAM probably non stop but Monitor is almost always off, and hard drive too. No GPU. Or is there a device I can get to measure it? Thx[/QUOTE] You can get a variety of in-line electricity meters; I own six. The i7/4770K box is 25W idle 90W flat-out, the Avoton is 20W idle 35W flat-out, the i7/4930K is 100W idle 160W flat-out 220W flat-out-with-GPGPU-on-top. The 48-core Opteron 6128 is about 300W idle and 550W flat-out. |
[QUOTE=fivemack;361905]You can get a variety of in-line electricity meters; I own six. The i7/4770K box is 25W idle 90W flat-out, the Avoton is 20W idle 35W flat-out, the i7/4930K is 100W idle 160W flat-out 220W flat-out-with-GPGPU-on-top. The 48-core Opteron 6128 is about 300W idle and 550W flat-out.[/QUOTE]
Please correct me if I'm wrong, but this is "in the CPUs". Measuring the total power draw on the DC rails is a little tougher.... |
Fluke and other makers have a bunch of clip-on probes/meters. If they measure DC current via clip-on probe, then they are using Hall effect sensors.
An (expensive for casual hobbyist) example is the [URL="http://www.fluke.com/fluke/inen/Accessories/Current-clamps/i410.htm?PID=56301"]Fluke i410[/URL], which is just a probe and used along with your multimeter. Of course there are cheaper units, [URL="http://www.amazon.com/Amprobe-ACDC-100-1000A-Clamp-Meter/dp/B001C6P38U/ref=sr_1_59?s=industrial&ie=UTF8&qid=1386885638&sr=1-59"]like this one via Amazon[/URL]. Hall effect sensors are often used with magnets as a contact-less substitute for magnet/reed switch combinations (as the mechanical reed switch is limited in lifetime and response rate). |
[QUOTE=fivemack;361905]You can get a variety of in-line electricity meters; I own six. The i7/4770K box is 25W idle 90W flat-out, the Avoton is 20W idle 35W flat-out, the i7/4930K is 100W idle 160W flat-out 220W flat-out-with-GPGPU-on-top. The 48-core Opteron 6128 is about 300W idle and 550W flat-out.[/QUOTE]
Thanks all but I think this is what I want....an inline meter.....and a few 48 cores :) |
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