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[QUOTE=RichD;312000]I'll take (3323^53-1)/(3323-1) C184
[SIZE=1]Mod note: [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]post 209[/URL][/SIZE][/QUOTE] Done. [CODE]prp77 factor: 46734885888095313337534966119007288522387634262813506482906421065181042932439 prp107 factor: 28188195379470209453078189735266116818099452752866115981501889434026866130147599277102446672981883202348479[/CODE] |
I'll take the two c186s,
(1487539^31-1)/(1487539-1) C186 (1583653^31-1)/(1583653-1) C186 [size=1]Mod note: [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]post 209[/URL][/size] |
I would like to reserve:
(2917^53-1)/(2917-1) C181 [size=1]Mod note: [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]post 209[/URL][/size] |
I've decided that the ECM I cited is sufficiently boring as to be put on hold and interject with doing one of these. As such, I'll do [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"](2957^53-1)/(2957-1) C181[/URL]. Carlos kindly provided me with the instructions to make a polynomial, but I'll want someone to verify that the other GGNFS params are at least somewhat optimal.
[code]n: 3050814277402253005216532590252942796387057798725128693786269369247133430781425434750331216918239346881571145099269367801565727743008617949625469906333072998219531813874210310000301 [STRIKE]m: 51110866676606486280448872612994249[/STRIKE] Y0: -17284702968077945985948215290157 Y1: 1 c0: -2957 c6: 1 degree: 6 skew: 0.26395189193 type: snfs rlim: 8312900 alim: 8312900 lpbr: 28 lpba: 28 mfbr: 55 mfba: 55 rlambda: 2.6 alambda: 2.6[/code] I get the feeling this is on the border between 13e and 14e; which should it be? With lpb==28, I should be expecting 20-25M rels? |
You have both m and Y1/Y0... anyway, m [STRIKE]will[/STRIKE] may be ignored but better keep it tidy and drop that line.
Also, c0: -[STRIKE]53[/STRIKE] 2957 |
c0 is wrong, it is -2957, therefore skew value is wrong, it is 0.263951892.
Edit: batalov posted at the same time. |
[QUOTE=Batalov;312452]You have both m and Y1/Y0... anyway, m [STRIKE]will[/STRIKE] may be ignored but better keep it tidy and drop that line.
Also, c0: -[STRIKE]53[/STRIKE] 2957[/QUOTE] [QUOTE=pinhodecarlos;312453]c0 is wrong, it is -2957, therefore skew value is wrong, it is 0.263951892. Edit: batalov posted at the same time.[/QUOTE] Whoops, base!=53 :blush: What about the siever? |
Today I added a C157 to the list in [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]post 209[/URL]. It would use a quartic. This joins the C171 and C175 not yet claimed. The new number is
[code] (2403293005054398937076590802836226619421^5-1)/(5*2403293005054398937076590802836226619420)[/code] |
[QUOTE=wblipp;312760]Today I added a C157 to the list in [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]post 209[/URL]. It would use a quartic. This joins the C171 and C175 not yet claimed. The new number is
[code] (2403293005054398937076590802836226619421^5-1)/(5*2403293005054398937076590802836226619420)[/code][/QUOTE] Whoops, scratch that, quartic, not quintic :razz: |
[QUOTE=Dubslow;312767]Whoops, scratch that, quartic, not quintic :razz:[/QUOTE]
Okay, on further thought, I believe this is the correct polynomial (and is quartic): [code]c4: 2403293005054398937076590802836226619421 c0: -1 m: 2403293005054398937076590802836226619421 # This is the same as Y0 == -m and Y1=1, right? skew: 7001670688 [/code] If so, then I'll do this when my [URL="http://www.mersenneforum.org/showthread.php?p=311744#post311744"]current reservation[/URL] is done (and I'll then do the C17*s if they're still available). [SIZE="1"](PS In case it's not clear, after some reading/thinking I'm pretty sure I can create polys now for most numbers of the form a^b+-1, and possibly other forms if I thought about those. I'd still like to be sure though :razz:)[/SIZE] Edit: Is there a way to take advantage of the apparently-larger-than-usual algebraic factor? (Meaning usually it's just a-1, but in this case it looks like b*(a-1).) |
No. The polynomial you want is x^4+x^3+x^2+x+1. The (x-1) factor of x^5-1 is already divided out.
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