To: CRGreathouse,

This is a [B][I]simple[/I][/B] question:

Let's consider the simple identity (T/T)*c^3=(T/T)*c^3,
where T can be viewed as some "[COLOR=red]cancelled common factor[/COLOR]".

Now, if we had to substitute c for T (or equivalently, c/c for T/T),
then would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(T/T)*c^3,
or would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(c/c)*c^3 ?

I say (c/c)*c^3=(c/c)*c^3 .

What do you say?

[QUOTE=Don Blazys;256932]To: CRGreathouse,

This is a [B][I]simple[/I][/B] question:

Let's consider the simple identity (T/T)*c^3=(T/T)*c^3,
where T can be viewed as some "[COLOR=red]cancelled common factor[/COLOR]".

Now, if we had to substitute c for T (or equivalently, c/c for T/T),
then would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(T/T)*c^3,
or would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(c/c)*c^3 ?

I say (c/c)*c^3=(c/c)*c^3 .

What do you say?[/QUOTE]

in my opinion both are accurate because left = right regardless of what c/c or t/t are present however you can only claim equivalence on the grounds that you must replace all values from one to the other without keeping any of one value intact. Why you brought it back up I have no idea as it's been settled.

That's [B][I]your[/I][/B] answer.

Now, what is CRGreathouse's answer?

To: CRGreathouse,

This is a [B][I]simple[/I][/B] question:

Let's consider the simple identity (T/T)*c^3=(T/T)*c^3,
where T can be viewed as some "[COLOR=red]cancelled common factor[/COLOR]".

Now, if we had to substitute c for T (or equivalently, c/c for T/T),
then would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(T/T)*c^3,
or would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(c/c)*c^3 ?

I say (c/c)*c^3=(c/c)*c^3 .

What do you say?

This reminds us how to play the famous master musician
[URL="http://en.wikiquote.org/wiki/Leonhard_Euler"]Euler[/URL] ...

" [URL="http://www.math.it/libri/equazione.htm"]it[/URL] [URL="http://www.webalice.it/mathi81/SHORTO-RUSSELL_LEOSSADICARTESIO.TXT"]is[/URL] [URL="http://it.answers.yahoo.com/question/index?qid=20100424033244AAlULMw"]the[/URL] [URL="http://www.google.it/search?hl=it&q=Signore%2C+%28a%2Bbn%29%2Fn%3Dx%2C+dunque+Dio+esiste%3B+risponda&aq=f&aqi=&aql=&oq="]music[/URL] .. [URL="http://dannyreviews.com/h/God_Equation.html"]do[/URL] .. "

[COLOR="LemonChiffon"]( So Don exist ? )[/COLOR]

[QUOTE=Don Blazys;256932]Now, if we had to substitute c for T (or equivalently, c/c for T/T),
then would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(T/T)*c^3,
or would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3=(c/c)*c^3 ?

I say (c/c)*c^3=(c/c)*c^3 .

What do you say?[/QUOTE]
[list][*] Substituting c for T is entirely different from substituting c/c for T/T, contrary to your claim.[*] (c/c)*c^3=(T/T)*c^3 is true, provided that neither c nor T is zero.[*] (c/c)*c^3=(c/c)*c^3 is true, provided that c is not zero.[/list]

To: CRGreathouse,

That's [B][I][U][COLOR=red]not[/COLOR][/U][/I][/B] the question!

You "copied and pasted" my post, then deleted the first
(and most important) part of the question because
you knew that you were wrong!

How disingenuous (or stupid) was that!?

Here again is the question, in its entirety,
with the part that you deleted, [B][I]enlarged:[/I][/B]

________________________________________________________________

[SIZE=4]To: CRGreathouse,[/SIZE]

[SIZE=4]This is a [B][I]simple[/I][/B] question:[/SIZE]

[SIZE=4]Let's consider the simple identity (T/T)*c^3 = (T/T)*c^3,[/SIZE]
[SIZE=4]where T can be viewed as some "[COLOR=red]cancelled common factor[/COLOR]". [/SIZE]

Now, if we had to substitute c for T (or equivalently, c/c for T/T),
then would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3 = (T/T)*c^3,
or would we be [B][I]consistent[/I][/B] in our [B][I]logic[/I][/B] if we wrote (c/c)*c^3 = (c/c)*c^3 ?

I say (c/c)*c^3 = (c/c)*c^3 .

What do you say?
_______________________________________________________________

Quoting CRGreathouse:
[QUOTE]
(c/c)*c^3=(T/T)*c^3 is true, provided that neither c nor T is zero.
[/QUOTE]Sorry, that is the [B][I]wrong[/I][/B] answer to my question because that equation
is [B][I]inconsistent[/I][/B] with the notion of cancelled [B][I][COLOR=red]common[/COLOR][/I][/B] factors.

In fact, here's how utterly illogical and silly your "reasoning" really is...

If:

T*a^x + T*b^y = T*c^z

and dividing both sides by T results in:

(T/T)*a^x + (T/T)*b^y = (T/T)*c^z,

then by [B][I][COLOR=red]your[/COLOR][/I][/B] reasoning, [B][I][COLOR=red]you[/COLOR][/I][/B] would substitute
N for T in one term only, so as to have:

(T/T)*a^x + (N/N)*b^y = (T/T)*c^z,

just because the "equality" is still maintained!

You can't even see that such a "substitution" would obviously imply that
the cancelled factors were not [B][I]common[/I][/B] at all and would therefore render
the entire equation nonsensical!!!!

Quoting CRGreathouse:
[QUOTE]
Substituting c for T is entirely different from substituting c/c for T/T[/QUOTE]That depends on the particular case that we are dealing with.
This can be demonstrated by the following experiment.

Take the identity: (T/T)*c^3 = (T/T)*c^3.

Now, on the left hand side, substitute c for T,
and on the right hand side, substitute (c/c) for (T/T).

The result, which is : (c/c)*c^3 = (c/c)*c^3,

clearly demonstrates that in this case (as in the case with my proof),

substituting c for T is [B][I]exactly the same[/I][/B] as substituting c/c for T/T.

Thus, you are [B][I]wrong[/I][/B] again, and have in no way refuted my
logical proof with your illogical (and frankly, idiotic) "reasoning".

My proof is irrefutable because it is a straightforward result that
requires no lawyer-like argument. In fact, this version of my proof:

[U][COLOR="Navy"]httр://donblazys.com/03.рdf[/COLOR][/U]

shows that my proof doesn't even require words!
It is simply an unavoidable consequence of logarithms!

Quoting CRGreathouse:
[QUOTE]
I prefer to think of myself as being a truth-seeker...
[/QUOTE]You have been exposed for the phoney that you are!

Don.

:popcorn:

I know we are not using the usual logic here so it makes following the arguments quite hard... Could someone clarify me if the following

[QUOTE=Don Blazys;257028]
If:

T*a^x + T*b^y = T*c^z

and dividing both sides by T results in:

(T/T)*a^x + (T/T)*b^y = (T/T)*c^z,
[/QUOTE]

is intended to follow from [B][I][U]CRGreathouse[/U][/I][/B]'s logic or from [B][COLOR="Green"]B[/COLOR][COLOR="YellowGreen"]l[/COLOR][COLOR="Orange"]az[/COLOR][COLOR="DarkOrange"]y[/COLOR][COLOR="Sienna"]s[/COLOR][/B]'?

[I]*takes a seat next to retina*[/I] and :popcorn:

[QUOTE=rajula;257030][I]*takes a seat next to retina*[/I] and :popcorn:[/QUOTE]<aol>Me too</aol> :popcorn:

[QUOTE=retina;257029]:popcorn:[/QUOTE]

:beer::beer::beer::beer::beer::beer::beer::beer: