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-   -   The KY-Conjectory (https://www.mersenneforum.org/showthread.php?t=15019)

davar55 2011-01-22 15:53

The KY-Conjectory
 
See the thread Wagstaff Conjecture in Puzzles or Math,
I'm not sure which.

-- davar55

davar55 2011-01-22 16:42

The crux of the YJ or YJ-Eb Conjecture is contained in the meaning of

lim(n->infinity) (M sub n) to-the (1 over n) = 3/2 = 1.500000 exactly.

See the whole conjecture under Wagstaff Conjecture in Math.

davar55 2011-01-22 18:29

This YJ-Conjecture was first presented here, in the Mersenne Forum,
by davar55 in 2006.

It was, I think, post #11 in a thread about our discovering M41.

Interesting that we're currently nearly proving the primality of
the first 41 Mersenne Primes.

davar55 2011-01-22 20:33

If anyone in this forum is interested in math
and has any questions here, I'd be glad to try
to answer them.

mdettweiler 2011-01-22 21:57

Pardon me, but how is this relevant to Conjectures 'R Us? I have seen some of the chatter about this conjecture in other parts of the forum and it seems to relate to Mersenne primes, not the generalized Sierpinski/Riesel conjectures and related k*b^n+-c primes that are discussed here. Perhaps you posted in the wrong forum?

Edit: Ah, I think I see where you may have been confused. Conjectures 'R Us is not intended as a place for posting of conjectures of all kinds; rather, it's a distributed project attempting to prove the generalized Sierpinski/Riesel conjectures.

davar55 2011-01-23 04:33

[QUOTE=mdettweiler;248516]Pardon me, but how is this relevant to Conjectures 'R Us? I have seen some of the chatter about this conjecture in other parts of the forum and it seems to relate to Mersenne primes, not the generalized Sierpinski/Riesel conjectures and related k*b^n+-c primes that are discussed here. Perhaps you posted in the wrong forum?

Edit: Ah, I think I see where you may have been confused. Conjectures 'R Us is not intended as a place for posting of conjectures of all kinds; rather, it's a distributed project attempting to prove the generalized Sierpinski/Riesel conjectures.[/QUOTE]

This YJ-Conjecture is in the Conjectures R Us sub-forum of
the Prime Search Projects sub-forum of MersenneForum Dot Org.

I suppose this thread might reasonably be moved to Math.

I have no objections.

mdettweiler 2011-01-23 04:47

[QUOTE=davar55;248624]This YJ-Conjecture is in the Conjectures R Us sub-forum of
the Prime Search Projects sub-forum of MersenneForum Dot Org.

I suppose this thread might reasonably be moved to Math.

I have no objections.[/QUOTE]
Okay, thanks--I've moved the thread to Math.

davar55 2011-01-23 04:54

[QUOTE=mdettweiler;248626]Okay, thanks--I've moved the thread to Math.[/QUOTE]

Sure, no problem. That's where it belongs anyway.

akruppa 2011-01-24 10:29

I question that. I've taken the logical next step and moved it to Misc. Math.

science_man_88 2011-01-24 13:56

[QUOTE=davar55;248386]The crux of the YJ or YJ-Eb Conjecture is contained in the meaning of

lim(n->infinity) (M sub n) to-the (1 over n) = 3/2 = 1.500000 exactly.

See the whole conjecture under Wagstaff Conjecture in Math.[/QUOTE]

how I interpret this is :

[CODE](09:53)>v=vector(10,n,if(n>1,2*v[n-1]+1,1))
%13 = [1, 3, 7, 15, 31, 63, 127, 255, 511, 1023]
(09:53)>for(n=1,#v,v[n]=v[n]^1/n)
(09:53)>v
%14 = [1, 3/2, 7/3, 15/4, 31/5, 21/2, 127/7, 255/8, 511/9, 1023/10]
(09:53)>for(n=1,#v,v[n]=v[n]-3/2)
(09:53)>v
%15 = [-1/2, 0, 5/6, 9/4, 47/10, 9, 233/14, 243/8, 995/18, 504/5][/CODE]

as you can see in the last v not all conform to v[n]<3/2, which blows the statement you supposedly lay your whole conjecture on to high heaven.even placing parentheses correctly I still get it false for both mersenne numbers and mersenne primes.

science_man_88 2011-01-24 14:55

[QUOTE=davar55;248413]
It was, I think, post #11 in a thread about our discovering M41.[/QUOTE]

I've tried one part I've never seen anywhere but that post and this is what I got:

[CODE](10:48)>v=[1, 3, 7, 15, 31, 63, 127, 255, 511, 1023, 2047]
%33 = [1, 3, 7, 15, 31, 63, 127, 255, 511, 1023, 2047]
(10:49)>for(i=1,#v,v[i]=v[i]/(3/2)^i)
(10:49)>v
%34 = [2/3, 4/3, 56/27, 80/27, 992/243, 448/81, 16256/2187, 21760/2187, 261632/19683, 349184/19683, 4192256/177147][/CODE]

how this helps I have no idea but I have a pattern in the fractions namely they are of the form 2x/3^y. what else are you saying about these ?


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