![]() |
[QUOTE=3.14159;227483]The size of the [B]largest[/B] prime factor is what determines how impressive it is:
Yes, CRG, even 3 * p10000 will be accepted into either Special or General cofactor.[/QUOTE] 10^10000 + 336030 = p1 . p1 . p10000, see [url]http://oeis.org/classic/A142587[/url] |
[QUOTE=CRGreathouse]10^10000 + 336030 = p1 . p1 . p10000, see [url]http://oeis.org/classic/A142587[/url][/QUOTE]
You go a long way to try and use your methods. |
[QUOTE=3.14159]You go a long way to try and use your methods.
[/QUOTE] @CRG: Now, I will truly congratulate you if you can give me a p(10^6) cofactor. Oh, right: 3 * (2[sup]43112609[/sup]-1)? |
[QUOTE=3.14159;227486]@CRG: Now, I will truly congratulate you if you can give me a p(10^6) cofactor.
Oh, right: 3 * (2[sup]43112609[/sup]-1)?[/QUOTE] Clearly, you have no appreciation for my minimalism. I would choose 3481 · 2[SUP]6816832[/SUP] - 59 · 2[SUP]3408417[/SUP] + 1. |
[QUOTE]Clearly, you have no appreciation for my minimalism. I would choose
59[sup]2[/sup] · 2[sup]6816832[/sup] - 59 · 2[sup]3408417[/sup] + 1.[/QUOTE] You tend to choose simple expressions. Why the sudden change of heart? |
Also: I'm sieving for k * 15661[sup]15661[/sup] + 1
P.S: Dammit, guys. You could have helped out with the searches. Sieved to 1.63 * 10[sup]12[/sup] for k * 13751[sup]13751[/sup] + 1 |
[QUOTE=3.14159;227489]You tend to choose simple expressions. Why the sudden change of heart?[/QUOTE]
Bigger number, smaller cofactor (while still being at least a million digits). |
Okay: For now, I'm going to be sieving. I have finally convinced myself to look for larger primes, optimally in the 30-70k digit range.
I have a 56300 and 65700 prime-based k-b-b search. Okay; Mods? No assistance? Come on, toss me a bone here! |
Well, in the meantime... A General Cofactor is coming up.
|
[QUOTE=3.14159;227492]Okay; Mods? No assistance? Come on, toss me a bone here![/QUOTE]
Exactly what kind of assistance are you looking for from the Mods? |
[QUOTE=axn]Exactly what kind of assistance are you looking for from the Mods?
[/QUOTE] Some assistance with the searches. By mods, I mean, the mods that visit here the most often. (Karsten, etc.) Also from other regular members. |
| All times are UTC. The time now is 23:13. |
Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.