[QUOTE=CRGreathouse;239504]I can't quite follow you, but
[code]n=0;
while(1,
print1(n++);
if(n>9, break);
print1(", ")
);[/code]
does the trick.[/QUOTE]


Wonder how fast we could finish off the list? You know most of them by the sounds of it. I'm still a little stumped on how to fix my rle script but I know ( and ) shouldn't be used to code something with. By the looks of it and I need ways to check for control characters,spaces and numbers that appear out of nowhere
in the strings but aren't part of the count of characters) maybe a Vec, and a scan of type will do but maybe not. I'm so stupid maybe tab in between would help lol.

if something can be done to files in the file system root:

[url]http://rosettacode.org/wiki/File_size[/url] the hard part to this one that must have landed it in the too hard category must be how to read the original given file size to compare something with.

[url]http://rosettacode.org/wiki/Pascal's_triangle/Puzzle[/url]

Doesn't sound hard in one sense.

solve:
[QUOTE]
[CENTER] [ 151]
[ ][ ]
[40][ ][ ]
[ ][ ][ ][ ]
[ X][11][ Y][ 4][ Z][/CENTER][/QUOTE]

first piece I can gather is x+y+22 = 40;so x+y=18 this is a fact to check for; also once a pair of x and y =18; also x+2y+z+30 = 151; so x+2y+z = 121; another fact to check for when going through z values.

[CODE]for(x=0,18,for(y=0,18,if(x+y=18,for(z=1,103,if((x+2*y+z)==121,print(x","y","z);break(3))))))[/CODE]

First one it found was 0,18,85 . It never says the program has to use only the data given, I used what I could gather.

[QUOTE=science_man_88;239513][CODE]for(x=0,18,for(y=0,18,if(x+y=18,for(z=1,103,if((x+2*y+z)==121,print(x","y","z);break(3))))))[/CODE]

First one it found was 0,18,85 . It never says the program has to use only the data given, I used what I could gather.[/QUOTE]

oops forgot y=x+z but that doesn't work I've messed up

I've determined y=13 by:


[ 6y+x+z+4a[2]+4a[4]= 7y +4a[2]+4a[4]]
[3y+x+37 ][3y+z+23]
[40=x+y+22][ 2y+15][ y+z+8 ]
[ x+11 ][y+11 ][y+4 ][z+4 ]
[ X][11][ Y][ 4][ Z]

if a = [] bottom row


for this sized triangle we see in this case 151-(44+16) = 91 ; 91/7 =13 y=13
40-13-22 =x = 5; 13-5=z=8;

however I now know how to solve it in this case.

[CODE] Pascals_triangle_puzzle(topvalue=151,leftsidevalue=40,bottomvalue1=11,bottomvalue2=4) = {
y=(topvalue-(4*(bottomvalue1+bottomvalue2)))/7;
x=leftsidevalue-(y+2*bottomvalue1);
z=y-x;
print(x","y","z); }[/CODE]

This easy enough ? I might try to make one for any size. just have to figure out the patterns lol.

I figured out how to falsify factoring a large number (somewhat);

[code][866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639 528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377]

[361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309 326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039][/code]

Which is.. [code]866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639[sup]528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377[/sup] * 361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309[sup]326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039[/sup][/code]

[QUOTE=3.14159;239539]I figured out how to falsify factoring a large number (somewhat);

[code][866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639 528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377]

[361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309 326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039][/code]

Which is.. [code]866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639[sup]528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377[/sup] * 361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309[sup]326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039[/sup][/code][/QUOTE]

finally Pi is back lol.

[QUOTE=science_man_88;239540]finally Pi is back lol.[/QUOTE]

Thanks. I get + 1 years added to my current age today.

[QUOTE=science_man_88;239506]so in other words if(string==type(0) ||string==type(1/2), print("this string is numerical")) would work ?[/QUOTE]

No.

if(type(string) == "t_STR", print("It's a string."))

[QUOTE=science_man_88;239506]Though I haven't covered floating point types.[/QUOTE]

t_REAL and t_COMPLEX.