[quote=R.D. Silverman;216956]I [B]gave[/B] an example.



OK. So, if this is your notation, you need to express 'a' as a function of
m. a depends on m.[/quote]
For m natural numbers.
a equals to 1 or m-1.
Further more: if m=4n or 5n we have a=1.
For n>1, natural number.

[QUOTE=blob100;216967]For m natural numbers.
a equals to 1 or m-1.
Further more: if m=4n or 5n we have a=1.
[/QUOTE]

No. Not quite.

e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.

let m = 10, the units are 1,3,7,9. Their product mod 10 is 9. This clearly
isn't 1.

[quote=R.D. Silverman;216971]No. Not quite.

e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.

let m = 10, the units are 1,3,7,9. Their product mod 10 is 9. This clearly
isn't 1.[/quote]
Keyboard writing mistake, I wanted to write n>2.

[QUOTE=blob100;216973]Keyboard writing mistake, I wanted to write n>2.[/QUOTE]

Now you are getting ridiculous. You are grossly incorrect.

Don't you bother [b]checking[/b] your answers by simple example???

[quote=R.D. Silverman;216989]Now you are getting ridiculous. You are grossly incorrect.

Don't you bother [B]checking[/B] your answers by simple example???[/quote]
Every natural number m, have a number a equals 1 or m-1 (for a, d(m) defined before).
For evey m with a residue class m-1, a=m-1.

Example:
m=16.
3*5=b(mod 16)
b=3*5=16-1.
And further more:
d(m)=a(mod 16)
a=16-1.

Where b is the residue class of (3,5).

[QUOTE=blob100;217134]Every natural number m, have a number a equals 1 or m-1 (for a, d(m) defined before).

[/QUOTE]

This is correct. Either a = 1 or a = -1 = m-1 mod m However:

(1) You need to justify your answer. How did you get it?
Show your work. It is not sufficient to simply assert the answer.

(2) You need to determine which m give the answer 1,
and which m give the answer -1.

Hint: This is closely related to a problem we already looked at. Think
about the units that are their own inverse.

[QUOTE=R.D. Silverman;216989]Now you are getting ridiculous. You are grossly incorrect.

Don't you bother [b]checking[/b] your answers by simple example???[/QUOTE]

Sometimes people just make mistakes. It isn't always a sign that they're feeble-minded. For example:

[QUOTE=R.D. Silverman;216971]e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.[/QUOTE]

[QUOTE=jyb;217145]Sometimes people just make mistakes. It isn't always a sign that they're feeble-minded. For example:[/QUOTE]

Students of mathematics need it drilled into them that they need to
check their answers.

[QUOTE=bsquared;203456]Assuming the poster is ESL (english as a second language), I would hold them to what you say for formal publication. Even then, it does not always happen: I've read numerous journal articles in which ESL authors didn't quite hit the mark but nonetheless were understandable and were published.

Discussion here should be a little more relaxed than formal publication standards, IMO.[/QUOTE]

He attacks anyone, even kids apparently. LOL. Having the moron on the ignore list is the best decision that I ever made. The sad guy even goes after children.. how tragic...

[QUOTE=3.14159;217175]He attacks anyone, even kids apparently. LOL. Having the moron on the ignore list is the best decision that I ever made. The sad guy even goes after children.. how tragic...[/QUOTE]

I like your humor.

[QUOTE=blob100;204009]The number 431is a good example for a non p (as I explained),
it is like putting 4 as a prime number because it is a natural number as a prime number is.
The number I told to put were prime numbers that are the factors of mersenne numbers with an odd exponential.
(I think you tought these are just prime numbers).
p isn't a normal prime number, it is a number as:
7,23,31,83...
You can see that 23's smallest odd factor that agrees 2[SUP]e(p-1)[/SUP]>p is 11 because 23's factors are 2,11.
83 and 7 are the same as 23.
31 is a more interesting,
31-1=30, and the smallest odd factor that agrees 2[SUP]e(p-1)[/SUP]>p is 5.
17 isn't a p number as I explained it is, because it's smallest factor that agrees 2[SUP]e(p-1)[/SUP]>p isn't an odd number (8 isn't an odd number).
Please read what I write before saying things are false.[/QUOTE]

431 is prime. Point debunked.

Proofs:
431/2 =/= Integer
431/3 =/= Integer
431/5 =/= Integer
431/7 =/= Integer
431/11 =/= Integer
431/13 =/= Integer
431/17 =/= Integer
431/19 = Integer
sqrt(431) = 20
431 is prime
QED