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[QUOTE=frmky;221213]ecm took care of it much more quickly[/QUOTE]
Step 2544 is a c169 (as it was today in the morning). Let's keep fingers crossed that ECM will do the job. |
worst case is a P85*P85... but i hope for a p59*p59*p60 or something around that.. or even a 4 way 40
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[QUOTE=firejuggler;221259]worst case is a P85*P85... but i hope for a p59*p59*p60 or something around that.. or even a 4 way 40[/QUOTE]
We'd rather have a p40 * p129. That sorts it out more quickly. |
@firejuggler: The factordb shows that you've done 1200 curves of P-1 and 560 curves of P+1. Say it ain't so!
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To clarify axn's post: it is pointless to run P-1 more than once - it [strike]will[/strike] should return the same result every time, finding a factor if there is one within the bounds. P+1 will find a factor (if it is within the bounds) about 1/2 of the time, so running it 3 times (which is normal) gives a ~7/8 chance of finding a factor if there is one within the bounds.
To clarify this further: "within the bounds" means that in the prime factorization of P-1 (for P-1) or P+1 (for P+1), the second-largest prime factor is below the B1 bound and the largest is below the B2 bound. |
axn, unfortunatly I did.... but not that much, i clicked 3 time for p-1 and twice for p+1...
my mouse is sometime disfonctional I will go to sleep less stupid tonight.. |
I've run 690 curves at B1=26e7. This represents a bit over 2*t45 but a bit less than 0.5*t50, so any factor will most likely be larger than 45 digits.
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[QUOTE=frmky;221272]I've run 690 curves at B1=26e7. This represents a bit over 2*t45 but a bit less than 0.5*t50, so any factor will most likely be larger than 45 digits.[/QUOTE]
I have done ~1000 curves at B1=3e6, no factor. Switching to 44e6 now. P.S.: According to our last c169, I think that we need ~17000@11e7 before switching to GNFS. |
[quote=FactorEyes;221104]Anything above C165 is not likely now - I was surprised we pulled that C171 and C169 in such quick succession.[/quote]
O'Reilly? |
[quote=10metreh;221223]Sequence 314718 has passed line 9000!
:party: [/quote] This is the first sequence to hit up with iteration (index) number 9000 Let us continue with that until it acquires a driver What are the chances of it to acquire a downdriver at this point at 171 digits with a factorization such as 8 times some prime of form 1 (mod 4)? |
[QUOTE=Andi47;221275]I have done ~1000 curves at B1=3e6, no factor. Switching to 44e6 now.
[/QUOTE] 68@44e6, no factor. I will stop for now due to summer heat. |
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