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-   -   Reserved for MF - Sequence 4788 (https://www.mersenneforum.org/showthread.php?t=11615)

Andi47 2009-11-25 10:20

[QUOTE=Andi47;196955]So - do we use 13e or 14e?[/QUOTE]

p-1: B1=5e8, B2=5e13, no factor
p+1: 3 runs at B1=1e8, B2=6e12, no factor.

Running some more ECM until it is decided, whether we use 13e or 14e.

fivemack 2009-11-25 11:17

4000 @ 4e7 completed, no factor.

Use 13e. I'll take 2M-6M.

Andi47 2009-11-25 11:53

[QUOTE=fivemack;196968]4000 @ 4e7 completed, no factor.

Use 13e. I'll take 2M-6M.[/QUOTE]

reserving 6M - 7M

fivemack 2009-11-25 13:35

taking 7M-9M

Mini-Geek 2009-11-29 19:51

Line 2472 is done. Line 2473, after only some very early prelim ECM (two Quick ECMs and partial aliqueit at B1=5e4) looks like 2^5*c169.
If this c169 is semiprime, what might happen to the guide?
Edit: Never mind, found a p23, c147 remaining. Survived 2 Quick ECMs and 100@5e4 so far.
Edit 2: Finished all 214@5e4, (25 digits) will also finish the 430@25e4 (30 digits) and do some P+-1.
Edit 3: Finished 430@25e4. (30 digits) Also did P-1, max B1 100M, and P+1, max B1 50M. All in DB. Not working on it any more ATM.

jrk 2009-11-29 20:50

[code]Using B1=43000000, B2=388112953420, polynomial Dickson(30), sigma=1315477237
Step 1 took 138222ms
Step 2 took 77110ms
********** Factor found in step 2: 4123290685142646964541600067761
Found probable prime factor of 31 digits: 4123290685142646964541600067761
Composite cofactor 83203877652763456216344080057649507874810835149655593949890433813292280209307613162194128906010127548847166175620653 has 116 digits
[/code]

I will do the c116

Andi47 2009-11-29 21:04

[QUOTE=jrk;197327][code]Using B1=43000000, B2=388112953420, polynomial Dickson(30), sigma=1315477237
Step 1 took 138222ms
Step 2 took 77110ms
********** Factor found in step 2: 4123290685142646964541600067761
Found probable prime factor of 31 digits: 4123290685142646964541600067761
Composite cofactor 83203877652763456216344080057649507874810835149655593949890433813292280209307613162194128906010127548847166175620653 has 116 digits
[/code]

I will do the c116[/QUOTE]

43e6 - opening eggs with nuclear warheads? :wink:

I have found the same c31 with B1=3e6 after 68 curves ~5 minutes ago. (I planned to run it overnight, but I stopped ECMing now, hence you started GNFS)

jrk 2009-11-29 21:54

c116 = p37.p37.p43

p37 = 3134160372909851723612253077515467493
p37 = 3636840079737787436938569640509488477
p43 = 7299584610785326987792600494916936890870973

jrk 2009-11-29 23:25

I'm doing the c109 now.

jrk 2009-11-30 03:41

[QUOTE=jrk;197332]I'm doing the c109 now.[/QUOTE]

Done.

[code]
prp54 factor: 481989758002837826944000482973711890329883965855795003
prp56 factor: 16617620933533935114464391289780146092392771482229686557

[/code]

jrk 2009-11-30 06:01

line 2476 c121 finished:

[code]
Using B1=3000000, B2=5706890290, polynomial Dickson(6), sigma=3159156024
Step 1 took 8056ms
Step 2 took 4090ms
********** Factor found in step 2: 13432838311461612250464777552146733002407
Found probable prime factor of 41 digits: 13432838311461612250464777552146733002407
Probable prime cofactor 130982517230425503437968877198264838192630336209630023456287838747078505224065181 has 81 digits

[/code]


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