[QUOTE=Drdmitry;449805]The driver has been lost [URL="http://factordb.com/sequences.php?se=1&aq=4788&action=last20"]again[/URL].
This song will play forever. :)[/QUOTE]

too bad all it will take for it to be a driver again ( okay 2^3 is a guide technically) is gaining a 5 or a 3. [URL="http://factordb.com/sequences.php?se=1&aq=255145911385930884813469706779422046222428384495923114580386266092670514219708202002510068356025542943673015531053573837009278762195360327910824476973993091288765112152&action=last&fr=0&to=100"]this[/URL] is a better link potentially if you don't want to look up the whole sequence and just see the last line.

[QUOTE=science_man_88;449806]too bad all it will take for it to be a driver again ( okay 2^3 is a guide technically) is gaining a 5 or a 3. [URL="http://factordb.com/sequences.php?se=1&aq=255145911385930884813469706779422046222428384495923114580386266092670514219708202002510068356025542943673015531053573837009278762195360327910824476973993091288765112152&action=last&fr=0&to=100"]this[/URL] is a better link potentially if you don't want ot look up the whole sequence and just see the last line.[/QUOTE]

2[SUP]3[/SUP] without a factor of 5 or 3 is not a guide. It will be stable until the power of two changes.

[QUOTE=Drdmitry;449808]2[SUP]3[/SUP] without a factor of 5 or 3 is not a guide. It will be stable until the power of two changes.[/QUOTE]

[url]http://www.rechenkraft.net/aliquot/analysis.html[/url] list it as a class 3 guide it may not class as a driver though.

[QUOTE=Drdmitry;449808]2[SUP]3[/SUP] without a factor of 5 or 3 is not a guide. It will be stable until the power of two changes.[/QUOTE]

In SM_88's link, I followed [URL="https://www.rechenkraft.net/aliquot/analysis.html"]Clifford Stern's definition[/URL]:

[quote]A guide consists of $2^a$ ($a \gt 0$) along with a subset of the prime factors of $\sigma(2^a)$.[/quote]

I interpreted it in the following way, which I believe to be at least perfectly reasonable if really just a question of meaningless semantics.

[quote]This motivates the following definition: a number of the form 2^b \cdot v, where v divides \sigma(2^b), is called a guide. (Note that when v=1, the guide is just the power of 2.)[/quote]

Actually, technically by your statement the down"driver" wouldn't be considered a guide. I think that is certainly enough to justify the empty powers of two as guides also...

Maybe it's time to change my username to [URL="https://en.wikipedia.org/wiki/Sisyphus"]Sisyphus[/URL]...

[QUOTE=ryanp;449837]Maybe it's time to change my username to [URL="https://en.wikipedia.org/wiki/Sisyphus"]Sisyphus[/URL]...[/QUOTE]
Told you so... Trust the [URL="https://en.wikipedia.org/wiki/Old_salt"]Old Salt [/URL]next time... :razz:
Now, don't be sad, from how the graph looks like, we may find the first cycle in the history of man, with a period 7000 or so... :w00t:

Ugh. The 7.

good, now it is me again who owns the largest downdriver! :razz:
(which is 613068, at 153 digits, not yet updated into Dubslow's table)

Well, don't get your hopes too low! :rolleyes:

[QUOTE=Batalov;450579]Well, don't get your hopes too low! :rolleyes:[/QUOTE]

Except that we're rapidly approaching 200 digits... :bangheadonwall:

Need that downdriver ASAP.

No progress from Jan 18, did Ryan still working on it?