3+3+2+2+1=11
 

[FONT="Courier New"]
".THREE"
".THREE"
"...TWO"
"...TWO"
"...ONE"
"======"
"ELEVEN"
[/FONT]

Wasn't sure how to get the spacing right without periods, anyway on to the puzzle:

Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality.

[code][FONT=Courier New] THREE
THREE
TWO
TWO
ONE
======
ELEVEN[/FONT][/code]Code tags. [ code ] [ /code ] (without the spaces)
Not so sure about the actual problem though...I was thinking [spoiler]E=1 since T+T = Ex, but since there's not just two numbers being added, I think it's possible for E to be something else[/spoiler]

[QUOTE=petrw1;144153]Substitute the appropriate digit for each corresponding letter to make a valid mathematical equality.[/QUOTE]Which base?

[QUOTE=Uncwilly;144155]Which base?[/QUOTE]

I have an answer for base 10 but if you want to try another base??

Actually since there are 9 different letters it can only be base 9 or 10 (and above?)

Clarification: The same digit CANNOT be assigned to two different letters

[SPOILER]84611
84611
..803
..803
..391
------
171219[/SPOILER]

axn1: Did you use brute force or were you able to solve much of it with logic?

It took me a couple hours (after restarting a couple times after dumb assumptions) on pencil and paper.

[QUOTE=petrw1;144237]brute force[/QUOTE]

:redface:

apart from the entirely trivial "e = 1" bit, that is.