hi,
to masser:
you do test the wrong base!
you should test R36 (base=36)

[QUOTE=masser;446183]4 primes found:

7399*6^445240-1
92943*6^477828-1
68535*6^487800-1
42623*6^490852-1

Testing continues.[/QUOTE]

Can you give us a current search depth?

[QUOTE=lalera;446184]hi,
to masser:
you do test the wrong base!
you should test R36 (base=36)[/QUOTE]

Exercise for the poster: 36^3 = 6^x. x = ?

Extending the concept: 36^n = 6^y. y = ?

Did you really think he posted a headline of base R36 and didn't notice the bases were different on his primes?

[QUOTE=VBCurtis;446197]Exercise for the poster: 36^3 = 6^x. x = ?

Extending the concept: 36^n = 6^y. y = ?

Did you really think he posted a headline of base R36 and didn't notice the bases were different on his primes?[/QUOTE]

hi,
for R6
k=1597 at n=5M remains
k=1597 testing for base 6 is the same as base 36 k=9582
for R36
39 k's remaining at n>=213K

7399*6^3-1 is prime!
92943*6^3-1 is prime!
68535*6^23-1 is prime!
42623*6^3-1 is prime!

it seems that mr. masser took the k´s from R36
and combined them with the wrong base 6
for R36 he should take 38 k´s (without k=9582) with base 36

[QUOTE=lalera;446212]hi,
for R6
k=1597 at n=5M remains
k=1597 testing for base 6 is the same as base 36 k=9582
for R36
39 k's remaining at n>=213K

7399*6^3-1 is prime!
92943*6^3-1 is prime!
68535*6^23-1 is prime!
42623*6^3-1 is prime!

it seems that mr. masser took the k´s from R36
and combined them with the wrong base 6
for R36 he should take 38 k´s (without k=9582) with base 36[/QUOTE]

You are missing the point. The base 6 primes that he posted are for base 36 k's. After all:

k*36^n-1 = k*6^(2n)-1

So therefore:
7399*6^445240-1
92943*6^477828-1
68535*6^487800-1
42623*6^490852-1

equals:

7399*36^222620-1
92943*36^238914-1
68535*36^243900-1
42623*36^245426-1

Those 4 k's were remaining for base 36 not base 6 before he found the primes. He is simply stating the base 36 primes in "reduced" form. I believe it may be somewhat faster to search squared (or other powers such as cubed or 5th power) bases in this manner so frequently searchers on here will post their primes in such a manner. At one time, one of our main searchers was posting base 243 primes in base 3 format because k*243^n-1 = k*3^(5n)-1.

[QUOTE=gd_barnes;446225]You are missing the point. The base 6 primes that he posted are for base 36 k's. After all:

k*36^n-1 = k*6^(2n)-1

So therefore:
7399*6^445240-1
92943*6^477828-1
68535*6^487800-1
42623*6^490852-1

equals:

7399*36^222620-1
92943*36^238914-1
68535*36^243900-1
42623*36^245426-1

Those 4 k's were remaining for base 36 not base 6 before he found the primes. He is simply stating the base 36 primes in "reduced" form. I believe it may be somewhat faster to search squared (or other powers such as cubed or 5th power) bases in this manner so frequently searchers on here will post their primes in such a manner. At one time, one of our main searchers was posting base 243 primes in base 3 format because k*243^n-1 = k*3^(5n)-1.[/QUOTE]

hi,
thank you for the explanation

[QUOTE=gd_barnes;446189]Can you give us a current search depth?[/QUOTE]

n=246000 (base 36); sorry for the confusion.

R36 Update
 

I completed testing R36 up to n=250,000. Releasing R36; candidates file attached. Those candidates were sieved up to Ps = 1.0e14.

Anyone interested should feel free to continue with attached file.

[QUOTE=masser;446960]I completed testing R36 up to n=250,000. Releasing R36; candidates file attached. Those candidates were sieved up to Ps = 1.0e14.

Anyone interested should feel free to continue with attached file.[/QUOTE]

Thanks. Can you send a results (residues) file?

[QUOTE=gd_barnes;446974]Thanks. Can you send a results (residues) file?[/QUOTE]

Done. Thanks for collecting the residues.

R63 tested to n=25k (15-25k) (137.6495M-145.37245M)

2545 primes found, 7455k left in this range

Results emailed, Base released

Note: 3 ranges left to n=25k